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umka21 [38]
3 years ago
6

Describe what you should do to recover only the water from a sample of muddy water.​

Chemistry
2 answers:
xz_007 [3.2K]3 years ago
4 0

Answer:

By using a filter.

Explanation:

zlopas [31]3 years ago
4 0
We can obtain clear water from a sample of muddy water by the process of filtration. In this method we use a filter paper which is fixed in funnel. Then the mixture is poured on the filter paper. Mud particles being larger in size will remain on the filter paper whereas clear water will pass through it.
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HELP ASAP! Chemical reactions involving liquids only will be influenced by ALL of the following EXCEPT: a) temperature of the sy
Rom4ik [11]
<span>Chemical reactions involving only liquids will be influenced by ALL of the following EXCEPT: </span><span><span>c) size of reactant particles d) pressure of the system.

</span>Reason:
1) As per Arrhenius theory, rate of chemical reactions is influence by temperature. Mathematically it is expressed as: k = A exp(-Ea/RT)
</span>where, k = rate constant, A = collision frequency, Ea = activation energy, T = temp. From above relation, it can be seen that, chemical reactions involving only liquids will be influenced temperature.

2) Also, if know that, rates of chemical reactions is mathematically expressed as: Rate = [A]^{x} B^{y}....,
where A, B, .. are the reactants.
From above relation, it can be seen that, chemical reactions involving only liquids will be influenced concentration i.e. number of particle. 

3) However, since all the reactant and catalyst used (if any) is in liquid state, particle size of same  will not influence the reaction.

4) Also, since there are no gas-phase reactant, pressure will not affect the reaction. 
8 0
3 years ago
What volume of 6.58M HCI is needed to make 500. mL of 3.00M HCI?
zmey [24]

Answer:

228 mL

Explanation:

M1*V1 = M2*V2

M1 = 6.58 M

V1 = ?

M2 = 3.00 M

V2 = 500 mL

V1 = M2*V2/M1 = 3.00M*500.mL/6.58 M = 228 mL

3 0
3 years ago
Which product formed when MgO and H2O react together?
seropon [69]
When MgO and H2O react they form Magnesium Hydroxide Mg(OH)2
4 0
3 years ago
Read 2 more answers
A 4.36 g sample of an unknown alkali metal hydroxide is dissolved in 100.0 ml of water. an acid-base indicator is added and the
Fofino [41]

Answer:

(a) 102.6g/mol

(b) Rubidium

Explanation:

Hello,

This titration is carried out by assuming that the volume of base doesn't have a significant change when the mass is added, thus, we state the following data a apply the down below formula to compute the molarity of the base solution:

V_{base}=0.1L; M_{acid}=2.5M, V_{acid}=0.017L\\V_{base}M_{base}=V_{acid}M_{acid}

Solving for the molarity of base we've got:

M_{base}=\frac{M_{acid}*V_{acid}}{V_{base}}=\frac{2.50M*0.017L}{0.1L} =0.425M=0.425mol/L

Now, we can compute the moles of the base as:

n_{base}=0.425mol/L*0.1L=0.0425mol

(a) Now, one divides the provided mass over the previously computed moles to get the molecular mass of the unknown base:

\frac{4.36g}{0.0425mol} =102.6g/mol

(b) Subtracting the atomic mass of oxygen and hydrogen, the metal's atomic mass turns out into:

102.6g/mol-16g/mol-1g/mol=85.6g/mol

So, that atomic mass dovetails to the Rubidium's atomic mass.

Best regards.

8 0
3 years ago
A certain sample of a liquid has a mass of 42 grams and a volume of 35 centimeters3. What is the density of the liquid?
BabaBlast [244]

Answer:

            1.2 g.cm⁻³

Solution:

Data Given:

                             Mass  =  42 g

                             Volume  =  35 cm³

Formula Used:

                             Density  =  Mass ÷ Volume

Putting values,

                             Density  =  42 g ÷ 35 cm³

                             Density  =  1.2 g.cm⁻³

3 0
3 years ago
Read 2 more answers
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