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Butoxors [25]
3 years ago
7

Which unit measures mass?

Chemistry
1 answer:
Artyom0805 [142]3 years ago
4 0

kilograms are the unit that measures mass

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What is a problem commonly associated with nuclear power facilities?
gregori [183]
(1) False, lots of energy is actually produced from nuclear fuel, if we didn't get much then we probably wouldn't use it
(2) False, its burning coal that contributes to acid rain, since it contains sulfur
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What two substances are formed at the end point of a neutralization reaction
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Relative mass each element contributes to the mass as a whole is _________.
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Select the correct answer from each drop-down menu. In a voltaic cell, the electrons and is oxidized, while the electrons and is
KengaRu [80]

Given what we know, we can confirm that in a voltaic cell, the anode loses electrons and is oxidized, meanwhile, the cathode is reduced by gaining electrons.

<h3 /><h3>What is a voltaic cell?</h3>
  • It is described as an electrochemical cell.
  • These cells use chemical reactions to produce electrical energy.
  • During this reaction, an anode loses electrons, thus oxidizing.
  • Meanwhile, the cathode gains electrons and is reduced.

Therefore, given the nature of the voltaic cell, we can confirm that during its reaction, the anode is oxidized by losing electrons while the cathode becomes reduced by gaining them.

To learn more about electrical energy visit:

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3 0
2 years ago
The empirical formula of an organic compound is C2H4O. The molecular mass of the compound is 176g/mol.
Brrunno [24]

Answer:

The molecular formula of the compound is C_{8}H_{16}O_{4}. The molecular formula is obtained by the following expression shown below

\textrm{Molecular formula }= n\times \textrm{Empirical formula}

Explanation:

Given molecular mass of the compound is 176 g/mol

Given empirical formula is  C_{2}H_{4}O

Atomic mass of carbon, hydrogen and oxygen are 12 u , 1 u and 16 u respectively.

Empirical formula mass of the compound = \left ( 2\times12+4+16 \right ) \textrm{ u} = 44 \textrm{ g/mol}

n = \displaystyle \frac{\textrm{Molecular formula mass}}{\textrm{Empirical formula mass}} \\n = \displaystyle \frac{176}{44} = 4

\textrm{Molecular formula }= n\times \textrm{Empirical formula}

Molecular formula = 4 \times C_{2}H_{4}O

Molecular formula is C_{8}H_{16}O_{4}

6 0
3 years ago
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