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dexar [7]
3 years ago
11

Which of the following are not single-displacement reactions?

Chemistry
1 answer:
Goshia [24]3 years ago
6 0

Answer:

\boxed{\text{B and C }}

Explanation:

In a single-displacement reaction, one element exchanges partners with another element in a compound.

\textbf{A. } \rm Fe + 2HCl \longrightarrow FeCl_2 + H_2

This is a single-displacement reaction, because the element Fe exchanges partners with H in HCl.

\textbf{B. } \rm KOH + HNO_3 \longrightarrow H_2O + KNO_3

This is not a single-displacement reaction, because it is a reaction between two compounds.

This is a double displacement reaction in which the K⁺ and H⁺ cations change partners with the anions.

\textbf{C. } \rm Na_2S + 2HCl \longrightarrow 2NaCl + H_2S

This is not a single-displacement reaction. It is another double displacement reaction, in which the Na⁺ and H⁺ cations change partners with the anions.

\textbf{D. } \rm Ca + 2HOH \longrightarrow Ca(OH)_2 + H_2

This is a single-displacement reaction, because the element Ca exchanges partners with H in H₂O.

\boxed{\textbf{B and C }} are not single-displacement reactions.

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When heat is applied to 80 grams of CaCO3, it yields 39 grams of B. Determine the percentage of the yield.
EleoNora [17]

The question is incomplete, the complete question is:

When heat is applied to 80 grams of CaCO3, it yields 39 grams of CaO Determine the percentage of the yield.

CaCO3→CaO + CO2

<u>Answer:</u> The % yield of the product is 87.05 %

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

We are given:

Given mass of CaCO_3 = 80 g

Molar mass of CaCO_3 = 100 g/mol

Putting values in equation 1, we get:

\text{Moles of }CaCO_3=\frac{80g}{100g/mol}=0.8mol

For the given chemical reaction:

CaCO_3\rightarrow CaO+CO_2

By stoichiometry of the reaction:

If 1 mole of CaCO_3 produces 1 mole of CaO

So, 0.8 moles of CaCO_3 will produce = \frac{1}{1}\times 0.8=0.8mol of CaO

We know, molar mass of CaO = 56 g/mol

Putting values in above equation, we get:

\text{Mass of CaO}=(0.8mol\times 56g/mol)=44.8g

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100 ......(2)

Given values:

Actual value of the product = 39 g

Theoretical value of the product = 44.8 g

Plugging values in equation 2:

\% \text{yield}=\frac{39 g}{44.8g}\times 100\\\\\% \text{yield}=87.05\%

Hence, the % yield of the product is 87.05 %

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Answer:

Yes A redox reaction can be a combination reaction.

Two elements are mixed in a combination reaction to produce a single product.

Explanation:

Example: water formula

2H2 + O2 → 2H2O

Oxygen is reduced in this reaction when electrons are transferred from hydrogen to oxygen and hydrogen is also oxidized since oxygen from hydrogen accepts electrons. Oxygen is the oxidizing agent and hydrogen is the reducing agent.

2H2 + O2 → 2H2O

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