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3 years ago

Please help me with this question!!

Mathematics

1 answer:

kramer3 years ago

4 0

Answer:acute

Step-by-step explanation:

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P= 2(i+w) what is the solution for I?

Dafna11 [192]

First you had to switch sides of equation.

$2(i+w)=p$

Then you divide by two from both sides of equation form.

$\frac{2(i+w)}{2}= \frac{p}{2}$

Simplify.

$i+w=\frac{p}{2}$

Next, subtract by i from both sides of equation form.

$i+w-i=\frac{p}{2}-i$

Finally, simplify by equation.

$w=\frac{p}{2}-i$

Final answer: $\boxed{w=p/2-i}$

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

8 0

3 years ago

What is the value of x in the equation 1.8-3.7x=4.2x+0.3<br><br>

wlad13 [49]

Answer:

15/79

Step-by-step explanation:

or in Alternate form is X= 0.1898734177215

5 0

2 years ago

SIMPLIFY(5x3 - 12x + 4) + (6x2 - 4x + 3)

Iteru [2.4K]

Answer:

5x3-6x2-4x+7...(a)

Step-by-step explanation:

(5x3-12x+4)+ (6x2-4x+3)

15-12x+4+12-4x+3

5x3-6x2-4x+7

5 0

3 years ago

When no K is divided by 27, 30, or 45, the remainder is 3. Find the smallest possible value of K. Can someone send me the calcul

Vlad [161]

Answer:

3 is the answer

6 0

3 years ago

A random sample of 77 fields of durum wheat has a mean yield of 27.427.4 bushels per acre and standard deviation of 5.755.75 bus

xz_007 [3.2K]

Answer:

[ 21.79, 33.0 ]

Step-by-step explanation:

Given:

Sample size, n = 7

Sample mean, μ = 27.4

Standard deviation, σ = 5.75

Confidence level is 99%

also, population is normal i.e normally distributed

Thus,

Confidence interval = μ ± $z\frac{\sigma}{\sqrt n}$

For confidence level of 99%

z-value = 2.58

Therefore,

Lower limit of Confidence interval = μ - $2.58\times\frac{5.75}{\sqrt{7}}$

Lower limit of Confidence interval = 27.4 - $2.58\times\frac{5.75}{\sqrt{7}}$

Lower limit of Confidence interval = 21.79

Upper limit of Confidence interval = μ + $2.58\times\frac{5.75}{\sqrt{7}}$

Upper limit of Confidence interval = 27.4 + $2.58\times\frac{5.75}{\sqrt{7}}$

Upper limit of Confidence interval = 33.00

Hence, confidence interval = [ 21.79, 33.0 ]

5 0

3 years ago