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2 years ago

Helppppppppppppppppppppppppppppppppppppppppppp

Mathematics

2 answers:

masya89 [10]2 years ago

6 0

Step-by-step explanation:

here's the answer to your question

Ostrovityanka [42]2 years ago

5 0

Answer:

Step-by-step explanation:

x $x^{9/7}=x^{1+2/7}=x*x^{2/7}=x*\sqrt[7]{x^{9} }$

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*pls help* <br> solve 7,8,9, and 10 for brainliest

ivanzaharov [21]

Answer:

#8 : x=15−y

#9: $\frac{c}{b} -\frac{ax}{b}$

#10: y=2A−x

#7: T= $\frac{P}{IR}$

Step-by-step explanation:

7 0

2 years ago

Please help me..will give all the good stuff

Anika [276]

1. 14 loaves are needed for 63 customers

2. 90 loaves

3. 4.5 loaf

Step by Step:

9/2= 4.5

4.5x4= 18

27/4.5=6

14x4.5=63

I multiplied and divided everything by 4.5 so one loaf of bread is 4.5.

(Correct me if I'm wrong)

I hope this helped! :)

6 0

2 years ago

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

2 years ago

Hi there can anyone help me with this question please

forsale [732]

Mean means average, so you would add the numbers up and divide by the amount of numbers in the set.

4 0

3 years ago

Solve for y in terms of x

Alika [10]

Answer:

(a) 3 - 2x - 2x² (b) -21

Step-by-step explanation:

given, y +2x² = 3 -2x

make y the subject:

y = 3 - 2x - 2x²

if y = f(x)

then

f(x) = 3 - 2x - 2x²

(b)<u> to find f(3) we need to replace x with 3:</u>

<u />

3 - 2(3) - 2*(3)²

-21

3 0

1 year ago