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3 years ago

Helppppppppppppppppppppppppppppppppppppppppppp

Mathematics

2 answers:

masya89 [10]3 years ago

6 0

Step-by-step explanation:

here's the answer to your question

Ostrovityanka [42]3 years ago

5 0

Answer:

Step-by-step explanation:

x $x^{9/7}=x^{1+2/7}=x*x^{2/7}=x*\sqrt[7]{x^{9} }$

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In 1999, there were 9860 Great Danes registered with the American Kennel Club. The number of registered Labrador Retrievers was

jekas [21]

Answer:

153,997 Labrador Retrievers

Step-by-step explanation:

Let's make an equation for this problem. We know that there were 9,860 Great Danes. The number of Labrador Retrievers was 6,997 more than 15 times the number of registered Great Danes. More than can be changed to a plus sign. 15 times the number of Great Danes is 15 times 9,860. The equation is now 15*9,860 + 6,997.

15*9,860 is 147,900

147,900 + 6,997 is 153,997.

7 0

2 years ago

Read 2 more answers

The cheerleader section is on the basketball court. Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards. How man

Lady_Fox [76]

Answer:

The area of the floor space is equal to 5.83 sq yards.

Step-by-step explanation:

Given that,

Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards.

We need to find how many square yards of floor space are taken up by one row of cheerleaders.

We know that, the area of a rectangle is given by :

A = lb

So,

$A=\dfrac{7}{4}\times \dfrac{10}{3}\\\\A=5.83\ yards^2$

So, the area of the floor space is equal to 5.83 sq yards.

5 0

3 years ago

12 divided by the sum of h and 2

irinina [24]

Putting this into expression form, it would be:
12 ÷ (h + 2)
Hope this helps!

6 0

3 years ago

John has decided to prepare an old field for his son's new horse. the length of the field is 10 meters less than 4 times its wid

tatuchka [14]

Answer: The total money invested in the field will be $1,623.80

Step-by-step explanation:

step 1

Find the dimensions of the field

Let

x -----> the length of the field

y -----> the width of the field

p=2(x+y)

p(4.80)=1,584

p=330m

we know that

The perimeter of the field is equal to

330=2(x+y)----> equation A

x=4y-10 ------> equation B

substitute equation B in equation A and solve for y

330=2(4y-10+y)

165=(5y-10)

5y=165+10

y+35

Find the value of x

x=4(35)-10+130

therefore

The length of the field is 130 meters and the width of the field is 35 meters

step 2

Find the area of the field

The area of the field is

A=xy

substitute

A=(130)(35)=4,550m2

step 3

Find the number of bags of seed

Divide the area by 460

4,550/460=9.89 bags

Round up to the nearest whole number

9.89 bags=10 bags

step 4

Find the cost of the seed

(10 )(3.98)=$19.8

step 5

Find the total money invested in the field

1,584+$39.8=$1,623.80

7 0

2 years ago

Read 2 more answers

Write a quadratic equation that has one solution, with an axis of symmetry of x=3

slava [35]

i dont no 44444 but thanks for the points

3 0

2 years ago