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ArbitrLikvidat [17]
3 years ago
5

Please helppppppppppp​

Physics
1 answer:
Leni [432]3 years ago
4 0

Answer: 4

Explanation:

when energy is greater then frequency should increase and wavelength should decrease.

Therefore answer is 4

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Does anyone know this?
e-lub [12.9K]
Explanation: The first one
Source: it literally has fusion in the name
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3 years ago
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Which of the following is an example of work?
EastWind [94]

Answer:

it's D

Explanation:

6 0
3 years ago
Standing on top of a building, Bob tosses a baseball straight up with an initial speed of 15 m/s. It takes 4.0 s for the ball to
r-ruslan [8.4K]

Answer:

48.26 m

Explanation:

time to goes up (till stop for a while in the air - maximum height)

vt = vo + a t

0 = 15 + g . t

0 = 15 + (-9.8) . t

9.8t = 15

t = 1.531 s

so the time left to goes down is

4.0 - 1.531 = 2.469 s

height from the top of building can find it by using

vo =√(2gh)

15 = √(2)(9.8).h

15² = 19.6h

h = 225/19.6 = 11.48 m

so the distance of maximum height to the ground is

t = √(2H/g)

2.469 = √(2H/9.8)

2.469² = 2H/9.8

6.096 = 2H/9.8

2H = 6.096 x 9.8 = 59.74 m

so the vertical distance of the building (or the building height's is)

H - h = 59.74 - 11.48 = 48.26 m

5 0
3 years ago
A simple hydraulic lift is made by fitting a piston attached to a handle into a 3.0-cm diameter cylinder. The cylinder is connec
stiv31 [10]

Answer:

Approximately 3.1 \times 10^4 \; \rm N (assuming that the acceleration due to gravity is g = 9.81\; \rm kg \cdot N^{-1}.)

Explanation:

Let A_1 denote the first piston's contact area with the fluid. Let A_2 denote the second piston's contact area with the fluid.

Similarly, let F_1 and F_2 denote the size of the force on the two pistons. Since the person is placing all her weight on the first piston:

F_1 = W = m \cdot g = 50\; \rm kg \times 9.81 \; \rm kg \cdot N^{-1} =495\; \rm N.  

Since both pistons fit into cylinders, the two contact surfaces must be circles. Keep in mind that the area of a square is equal to \pi times its radius, squared:

  • \displaystyle A_1 = \pi \times \left(\frac{1}{2} \times 3.0\right)^2 = 2.25\, \pi\;\rm cm^{2}.
  • \displaystyle A_2 = \pi \times \left(\frac{1}{2} \times 24\right)^2 = 144\, \pi\;\rm cm^{2}.

By Pascal's Law, the pressure on the two pistons should be the same. Pressure is the size of normal force per unit area:

\displaystyle P = \frac{F}{A}.

For the pressures on the two pistons to match:

\displaystyle \frac{F_1}{A_1} = \frac{F_2}{A_2}.

F_1, A_1, and A_2 have all been found. The question is asking for F_2. Rearrange this equation to obtain:

\displaystyle F_2 = \frac{F_1}{A_1} \cdot A_2 = F_1 \cdot \frac{A_2}{A_1}.

Evaluate this expression to obtain the value of F_2, which represents the force on the piston with the larger diameter:

\begin{aligned}F_2 &= F_1 \cdot \frac{A_2}{A_1} \\ &= 495\; \rm N \times \frac{2.25\, \pi\; \rm cm^2}{144\, \pi \; \rm cm^2} \approx 3.1 \times 10^4\; \rm N\end{aligned}.

6 0
3 years ago
The following equation is an example of decay?<br><br> 232/90 TH---4/2 HE +228/88 RA?
DaniilM [7]

Answer:

Alpha decay

Explanation:

  • Alpha decay is one of the three major types of decays, others being, beta decay and gamma decay.
  • <em><u>When a radioactive isotope undergoes alpha decay it emits alpha particles. An alpha particle is equivalent to the nucleus of Helium atom.</u></em>
  • <em><u>Therefore, an atom undergoing decay, its atomic mass is decreased by 4 and its atomic number is decreased by 2. </u></em>
  • Thus, since 232/90 Th, has undergone alpha decay its mass number is reduced by 4 to 228 and its atomic number by 2 to 88, and becomes 228/88 Ra.
5 0
3 years ago
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