Answer:
The ratio of the Broglie wavelength of an electron to that of the proton is 42.85.
Explanation:
let λe be the Broglie wavelength of the electron and λp be the Broglie wavelength of the proton, Me be the mass of the electron and Mp be the mass of the proton. let h be the Planck constant, Kep be the kinetic energy of the proton and KEe be the kinetic energy of the electron
Answer:
(a) 83475 MW
(b) 85.8 %
Explanation:
Output power = 716 MW = 716 x 10^6 W
Amount of water flows, V = 1.35 x 10^8 L = 1.35 x 10^8 x 10^-3 m^3
mass of water, m = Volume x density = 1.35 x 10^8 x 10^-3 x 1000
= 1.35 x 10^8 kg
Time, t = 1 hr = 3600 second
T1 = 25.4° C, T2 = 30.7° C
Specific heat of water, c = 4200 J/kg°C
(a) Total energy, Q = m x c x ΔT
Q = 1.35 x 10^8 x 4200 x (30.7 - 25.4) = 3 x 10^12 J
Power = Energy / time
Power input =
Power input = 83475 MW
(b) The efficiency of the plant is defined as the ratio of output power to the input power.


Thus, the efficiency is 85.8 %.
Let P1=13m/s(1250kg)=16250 kg m/s (positive velocity is north here)
P2=-19m/s(1250kg)=-23750 kg m/s
Total system momentum is P1 + P2 = 16250 - 23750 = -7500 (negative momentum is south pointing).
Due to the conservation of momentum, this is also the final momentum and we see the two cars have a mass of 1250 + 1250 = 2500kg and have a velocity
-7500 = 2500kg * Vfinal
Final = -3m/s (moving southward)
Each car's momentum changes from the initial value it had to this final value, but the total system momentum does not change, due to the conservation law.