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2 years ago

Please help ill give brainly !

Chemistry

2 answers:

nlexa [21]2 years ago

6 0

Amount of wind in each area of the earth
i hope it’s correct, if it’s not sorry !

soldi70 [24.7K]2 years ago

3 0

Answer:

Explanation:

The Earth is a sphere and around the equator is where the closest parts of the Earth are to the Sun, while places like Antarctica are the furthest away from the Sun.

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Caffeine (C8H10N4O2) is a weak base with a pKb of 10.4. Calculate the pH of a solution containing a caffeine concentration of 41

RSB [31]

Answer:

pH → 7.47

Explanation:

Caffeine is a sort of amine, which is a weak base. Then, this pH should be higher than 7.

Caffeine + H₂O ⇄ Caffeine⁺ + OH⁻ Kb

1 mol of caffeine in water can give hydroxides and protonated caffeine.

We convert the concentration from mg/L to M

415 mg = 0.415 g

0.415 g / 194.19 g/mol = 2.14×10⁻³ mol

[Caffeine] = 2.14×10⁻³ M

Let's calculate pH. As we don't have Kb, we can obtain it from pKb.

- log Kb = pKb → 10^-pKb = Kb

10⁻¹⁰'⁴ = 3.98×10⁻¹¹

We go to equilibrium:

Caffeine + H₂O ⇄ Caffeine⁺ + OH⁻ Kb

Initially we have 2.14×10⁻³ moles of caffeine, so, after the equilibrium we may have (2.14×10⁻³ - x)

X will be the amount of protonated caffeine and OH⁻

Caffeine + H₂O ⇄ Caffeine⁺ + OH⁻ Kb

(2.14×10⁻³ - x) x x

We make the expression for Kb:

3.98×10⁻¹¹ = x² / (2.14×10⁻³ - x)

We can missed the -x in denominator, because Kb it's a very small value.

So: 3.98×10⁻¹¹ = x² / 2.14×10⁻³

√(3.98×10⁻¹¹ . 2.14×10⁻³) = x → 2.92×10⁻⁷

That's the [OH⁻]. - log [OH⁻] = pOH

- log 2.92×10⁻⁷ = 6.53 → pOH

14 - pOH = pH → 14 - 6.53 = 7.47

4 0

3 years ago

Why isn't every point exactly on the 'best fit line'? Give a reason and explain

vampirchik [111]

Answer:

thats all help me too:)...............

5 0

3 years ago

Benzene is an organic chemical compound with the molecular formula C6H6. In the benzene molecule, carbon atoms form a ring with

Sergeu [11.5K]

Answer:

$sp^2$

Explanation:

Hello,

The six-carbon benzene ring contains two types of bonds: C-C and C-H bonds, that are $sp^2$ -hybridized σ bonds, and the six π bonds that form the aromatic ring. The σ bonds form from one $s$ orbital and two $p$ orbitals from each carbon, which then bond the carbon to the two carbons on either side and the carbon's single hydrogen. The remaining $p$ orbital from each carbon atom sticks out above and below the plane of the ring; these $p$ orbitals overlap sideways, rather than lengthwise, to form the aromatic π bond system.