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mart [117]
3 years ago
14

0.01 M HCl solution has a pH of 2. Suppose that during the experiment, both the universal pH indicator and the cabbage indicator

turn orange-red for 0.01 M HCl. What can you conclude about the the cabbage indicator key?
Chemistry
4 answers:
evablogger [386]3 years ago
6 0
A) It matches the universal pH indicator and is indicating the proper pH. Yes, this is correct. Have a great day!
NNADVOKAT [17]3 years ago
5 0
It matches the universal pH indicator and is indicating the proper pH
zvonat [6]3 years ago
5 0

Answer:

A ) it matches the universal pH indicator and is indicating the proper pH

Novay_Z [31]3 years ago
4 0
YOU ARE PROBABLY CHEATING RIGHT NOW!!! ... that's cool ig...
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Look at the picture of two different substances above. Which substance is a mixture? A. Y and Z
Feliz [49]

Answer:

option B is correct.

Y is a mixture in the picture.

Explanation:

Different types of substances combine physically and form a mixture.  

Mixture formed by the combination of two or more substances that that combine in same physical state.

For example mixture of copper sulphate and solid chloride in dry form and that will look like white and blue crystal in a mixture.

The picture Z showing dots of same color and is not a mixture, while picture Y shows dots of different colors clearly indicating that it is picture for mixture.

5 0
3 years ago
Read 2 more answers
I will take a picture of the question ​
a_sh-v [17]

Answer:

yes as you wish

Explanation:

but why have u asked this

3 0
3 years ago
A solution is prepared by dissolving 2.61 g ethanol (C2H5OH) in 16.2 g water. What is the molality (mol/kg) of C2H5OH in the sol
stiks02 [169]

Answer:

3.50 molal

Explanation:

Molality → Moles of solute / kg of solvent.

Let's convert the solvent's mass from g to kg

16.2 g . 1kg / 1000 g = 0.0162 kg

Let's determine the moles from the solute

2.61 g . 1 mol / 46 g = 0.0567 moles

Molality → 0.0567 mol / 0.0162 kg = 3.50 m

7 0
3 years ago
Help thank you so so much!
Otrada [13]

Answer:

D is the answer to this problem

8 0
3 years ago
An experiment shows that a 236 mL gas sample has a mass of 0.443 g at a pressure of 740 mmHg and a temperature of 22 ∘C. What is
aleksley [76]

Answer:

49.2 g/mol

Explanation:

Let's first take account of what we have and convert them into the correct units.

Volume= 236 mL x (\frac{1 L}{1000 mL}) = .236 L

Pressure= 740 mm Hg x (\frac{1 atm}{760 mm Hg})= 0.97 atm

Temperature= 22C + 273= 295 K

mass= 0.443 g

Molar mass is in grams per mole, or MM= \frac{mass}{moles} or MM= \frac{m}{n}. They're all the same.

We have mass (0.443 g) we just need moles. We can find moles with the ideal gas constant PV=nRT. We want to solve for n, so we'll rearrange it to be

n=\frac{PV}{RT}, where R (constant)= 0.082 L atm mol-1 K-1

Let's plug in what we know.

n=\frac{(0.97 atm)(0.236 L)}{(0.082)(295K)}

n= 0.009 mol

Let's look back at MM= \frac{m}{n} and plug in what we know.

MM= \frac{0.443 g}{0.009 mol}

MM= 49.2 g/mol

3 0
3 years ago
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