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Scrat [10]
2 years ago
6

What’s number 1, 2, 3 Major grade 6th grade

Chemistry
1 answer:
Maslowich2 years ago
8 0

Answer:

1 is B

2 is A

3 is A

Explanation:

Hope you pass

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How many moles of water in 100 grams
Bond [772]

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There are approximately 5.55 moles

Explanation:

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2 years ago
Manoa falls drops 153 feet, measured the bottom to be 663 liters per second
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Answer:

Manoa

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likeke

Explanation:

4 0
2 years ago
The nucleus of one lithium atom has three protons and four neutrons. what is the total charge of the lithium nucleus.
Xelga [282]
Since protons are postive and neutrons are neutral. Then it is postive.
6 0
3 years ago
Read 2 more answers
The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
Kipish [7]

Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

According to stoichiometry:

1 mole of C_3H_8 requires 5 moles of oxygen

0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

Mass of O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g

72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

7 0
3 years ago
5. What volume of silver metal will weigh exactly 4500.0 g. The density of silver is 20.5 g/cm.
Vitek1552 [10]

Answer:

The answer is

<h2>219.5 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 4500 g

density = 20.5 g/cm³

We have

volume =  \frac{4500 }{20.5}  \\  = 219.51219...

We have the final answer as

<h3>219.51 mL</h3>

Hope this helps you

8 0
2 years ago
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