Answer:
Number of iodine atoms = 2 × 4 = 8
Number of oxygen atoms = 2 × 9 = 18
Explanation:
Coefficient 2 is placed in front of the product tetraiodine nonaoxide:
= 
Number of iodine atom in a single molecule tetraiodine nonaoxide = 4
Number of oxygen atoms in a single molecule tetraiodine nonaoxide = 9
Coefficient 2 is placed in front of the product tetraiodine nonaoxide:
=
Number of iodine atoms = 2 × 4 = 8
Number of oxygen atoms = 2 × 9 = 18
multiply the number of each atom with its molecular mass. (see the periodic table)
5*12 + 12*1 = 72 gram per mole.
Or more accurately: 5*12.01078 + 12*1.007947 = 72.149264 g/mole
the rocky planet was exposed to harsh and forceful solar winds, which blew the Martian atmosphere away.
Another option for thickening the atmosphere of Mars, and, in turn, raising the temperature of the planet, would be to set up solar-powered, greenhouse-gas producing factories.
Answer:
P₂ = 2.88 atm
Explanation:
Given data:
Initial volume of gas = 1.8 L
Final volume = 750 mL
Initial pressure = 17.5 Psi
Final pressure = ?
Solution:
We will convert the units first:
Initial pressure = 17.5 /14.696 = 1.2 atm
Final volume = 750 mL ×1L/1000L = 0.75 L
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
1.2 atm × 1.8 L = P₂ ×0.75 L
P₂ = 2.16 atm. L/ 0.75 L
P₂ = 2.88 atm
Answer
The volume of the container that the gas is in = 874.30 L
Explanation
Given:
Moles, n = 3.2 mol
Pressure, P = 0.095 atm
Temperature, T = 43 °C = (43 + 273.15 K) = 316.15 K
Molar gas constant, R = 0.0821 atm•L/mol•K
What to find:
The volume of the container that the gas occupied.
Step-by-step solution:
The volume of the container that the gas occupied can be calculated using the ideal gas equation.
Therefore, the volume of the container that the gas occupied is 874.30 L
