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Brilliant_brown [7]
2 years ago
12

What fitness components can impact a soccer players performance?

Physics
1 answer:
NemiM [27]2 years ago
6 0

Answer:

C) Cardiovascular, muscular strength/power, muscular endurance

Explanation:

I did take the quiz

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Explanation:

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a jumping flea accelerates att 500m/s^2 over a distance of 0.50mm st a 30 degree angle how far does this flea leap
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What three forces contribute to the rise of water in a capillary tube?
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These three forces are cohesive force, adhesive force and surface tension. The cohesive and adhesive forces are opposite of each other. While cohesive force is the intermolecular bonding between like molecules, the adhesive force is the intermolecular force between unlike molecules. Surface tension is perceived to be the force exerted by the liquid near the surface of the water. Together, these forces bring about an increase in liquid height when a very small tube is placed on a wide surface liquid.
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3 years ago
Evaporation of sweat requires energy and thus take excess heat away from the body. Some of the water that you drink may eventual
kotegsom [21]

Answer:

The amount of heat required is H_t =  1.37 *10^{6} \ J

Explanation:

From the question we are told that

The mass of water is m_w  =  20 \ ounce = 20 * 28.3495 = 5.7 *10^2 g

The temperature of the water before drinking is T_w  =  3.8 ^oC

The temperature of the body is T_b  =  36.6^oC

Generally the amount of heat required to move the water from its former temperature to the body temperature is

H=  m_w  *  c_w * \Delta T

Here c_w is the specific heat of water with value c_w = 4.18 J/g^oC

So

H=   5.7 *10^2 * 4.18 * (36.6 - 3.8)

=> H= 7.8 *10^{4} \  J

Generally the no of mole of sweat present mass of water is

n = \frac{m_w}{Z_s}

Here Z_w is the molar mass of sweat with value

Z_w =  18.015 g/mol

=> n = \frac{5.7 *10^2}{18.015}

=> n = 31.6 \  moles

Generally the heat required to vaporize the number of moles of the sweat is mathematically represented as

H_v  =  n  *  L_v

Here L_v is the latent heat of vaporization with value L_v  = 7 *10^{3} J/mol

=> H_v  =  31.6 * 7 *10^{3}

=> H_v  = 1.29 *10^{6} \  J

Generally the overall amount of heat energy required is

H_t =  H +  H_v

=> H_t =  7.8 *10^{4} +  1.29 *10^{6}

=> H_t =  1.37 *10^{6} \ J

4 0
3 years ago
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