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Brilliant_brown [7]
2 years ago
12

What fitness components can impact a soccer players performance?

Physics
1 answer:
NemiM [27]2 years ago
6 0

Answer:

C) Cardiovascular, muscular strength/power, muscular endurance

Explanation:

I did take the quiz

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In this experiment we will observe the magnetic fields produced by a current carrying wire. A long wire is suspended vertically,
Alisiya [41]

Answer:

See explanation

Explanation:

Solution:-

Electric current produces a magnetic field. This magnetic field can be visualized as a pattern of circular field lines surrounding a wire. One way to explore the direction of a magnetic field is with a compass, as shown by a long straight current-carrying wire in. Hall probes can determine the magnitude of the field. Another version of the right hand rule emerges from this exploration and is valid for any current segment—point the thumb in the direction of the current, and the fingers curl in the direction of the magnetic field loops created by it.

Compasses placed near a long straight current-carrying wire indicate that field lines form circular loops centered on the wire. Right hand rule 2 states that, if the right hand thumb points in the direction of the current, the fingers curl in the direction of the field. This rule is consistent with the field mapped for the long straight wire and is valid for any current segment.

( See attachments )

- The equation for the magnetic field strength - B - (magnitude) produced by a long straight current-carrying wire is given by the Biot Savart Law:

                                  B = \frac{uo*I}{2\pi *r}

Where,

I : The current,

r : The shortest distance to the wire,

uo : The permeability of free space. = 4π * 10^-7  T. m/A

-  Since the wire is very long, the magnitude of the field depends only on distance from the wire r, not on position along the wire. This is one of the simplest cases to calculate the magnetic field strength - B - from a current.

- The magnetic field of a long straight wire has more implications than one might first suspect. Each segment of current produces a magnetic field like that of a long straight wire, and the total field of any shape current is the vector sum of the fields due to each segment. The formal statement of the direction and magnitude of the field due to each segment is called the Biot-Savart law. Integral calculus is needed to sum the field for an arbitrary shape current. The Biot-Savart law is written in its complete form as:

                             B = \frac{uo*I}{4\pi }*\int\frac{dl xr}{r^2}      

Where the integral sums over,

 1) The wire length where vector dl = direction of current (in or out of plane)

 2) r is the distance between the location of dl and the location at which the magnetic field is being calculated

 3)  r^ is a unit vector in the direction of r.

   

3 0
3 years ago
In a paragraph, answer these questions:
mixer [17]

the process by which green plants and some other organisms use sunlight to synthesize foods from carbon dioxide and water. Photosynthesis in plants generally involves the green pigment chlorophyll and generates oxygen as a byproduct.The inputs of photosynthesis are light energy, and matter in the form of water absorbed through the roots, and carbon dioxide absorbed through the leaves.The main outputs are oxygen, which is released into the air, and glucose sugar (chemical energy), which is used to keep the plant alive.

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A toy car on a string is pulled across a table horizontally. The string is at an angle
ddd [48]
Which way is it being pulled?
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3 years ago
What are some examples of a solute
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Anything that can be dissolved/mixed into a solvent. Sugar, salt, acetic acid, etc
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3 years ago
A 12 cm diameter piston-cylinder device contains air at a pressure of 100 kPa at 24oC. The piston is initially 20 cm from the ba
lina2011 [118]

Answer:

ΔQ = 0.1 kJ

\mathbf{v_f = 1.445*10^{-3}  m^3}

\mathbf{P_f = 156.5 \ kPa}

ΔS = -0.337 J/K

The value negative is due to the fact that there is need to be the same amount of positive change in surrounding as a result of compression.

Explanation:

GIven that:

Diameter of the piston-cylinder = 12 cm

Pressure of the piston-cylinder = 100 kPa

Temperature =24 °C

Length of the piston = 20 cm

Boundary work ΔW = 0.1 kJ

The gas is compressed and The temperature of the gas remains constant during this process.

We are to find ;

a. How much heat was transferred to/from the gas?

According to the first law of thermodynamics ;

ΔQ = ΔU + ΔW

Given that the temperature of the gas remains constant during this process; the isothermal process at this condition ΔU = 0.

Now

ΔQ = ΔU + ΔW

ΔQ = 0 + 0.1 kJ

ΔQ = 0.1 kJ

Thus; the amount of heat that was transferred to/from the gas is : 0.1 kJ

b. What is the final volume and pressure in the cylinder?

In an isothermal process;

Workdone W = \int dW

W = \int pdV \\ \\ \\W = \int \dfrac{nRT}{V}dv \\ \\ \\ W = nRt \int  \dfrac{dv}{V}  \\ \\ \\ W  = nRT In V |^{V_f} __{V_i}}  \\ \\ \\ W = nRT \ In \dfrac{V_f}{V_i}

Since the gas is compressed ; then v_f< v_i

However;

W =- nRT \ In \dfrac{V_f}{V_i}

W =- P_1V_1  \ In \dfrac{V_f}{V_i}

The initial volume for the cylinder is calculated as ;

v_1 = \pi r^2 h \\ \\   v_1 = \pi r^2 L \\ \\ v_1 = 3.14*(6*10^{-2})^2*(20*10^{-2}) \\ \\ v_1 = 2.261*10^{-3} \ m^3

Replacing over values into the above equation; we have :

100 =  - ( 100*10^3 *2.261*10^{_3}) In (\dfrac{v_f}{v_i}) \\ \\ - In (\dfrac{v_f}{v_i})= \dfrac{100}{(100*10^3*2.261*10^{-3})} \\ \\ - In \ v_f  + In \  v_i = \dfrac{100}{226.1} \\ \\   - In \ v_f  = - In \ v_i + \dfrac{100}{226.1}  \\ \\  - In \ v_f  = - In (2.261*10^{-3} + \dfrac{100}{226.1 } \\ \\  - In \ v_f  = 6.1 + 0.44 \\ \\  - In \ v_f  = 6.54 \\ \\  - In \ v_f  = -6.54 \\ \\ v_f = e^{-6.54} \\ \\ \mathbf{v_f = 1.445*10^{-3}  m^3}

The final pressure can be calculated by using :

P_1V_1 = P_2V_2 \\ \\ P_iV_i = P_fV_f

P_f =\dfrac{P_iV_i}{V_f}

P_f =\dfrac{100*2.261*10^{-3}}{1.445*10^{-3}}

P_f = 1.565*10^2 \ kPa

\mathbf{P_f = 156.5 \ kPa}

c. Find the change in entropy of the gas. Why is this value negative if entropy always increases in actual processes?

The change in entropy of the gas is given  by the formula:

\Delta S=\dfrac{\Delta Q}{T}

where

T =  24 °C = (24+273)K

T = 297 K

\Delta S=\dfrac{-100 \ J}{297 \ K}

ΔS = -0.337 J/K

The value negative is due to the fact that there is need to be the same amount of positive change in surrounding as a result of compression.

4 0
3 years ago
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