A chemist dilutes a 1.0 ml sample of 2.0M KNO₃ by adding water to it. If the concentration of the solution that is obtained is 0.0080 m, then its volume is 250mL.
<h3>How do we calculate volume?</h3>
Volume for the given equation will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
M₁ = molarity of KNO₃ = 2M
V₁ = volume of KNO₃ = 1mL
M₂ = molarity of final solution = 0.0080M
V₂ = volume of final solution = ?
On putting these values on the above equation, we get
V₂ = (2)(1) / (0.0080) = 250mL
Hence option (2) is correct.
To know more about molarity, visit the below link:
brainly.com/question/24305514
Mass in kilograms of liquid air required = 0.78 kg
<u>Given that </u>
1 Litre of liquid air contains 1.3 grams of oxygen ( air )
<u />
<u> Determine the a</u><u>mount of liquid air</u><u> in Kg</u>
volume of air given = 600 L
mass of liquid air required = x
1 litre = 1.3 grams
600 L = x
∴ x ( mass of liquid air ) = 1.3 * 600
= 780 g = 0.78 kg
Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg
Learn more about liquid air : brainly.com/question/636295
The answer is D
I took the test and I got this answer, it was correct :)
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