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kumpel [21]
3 years ago
8

Which of the following statements is true? A. Some plants are considered abiotic components of an ecosystem. B. Animals are alwa

ys biotic components of an ecosystem. C. Temperature range is always a biotic component of an ecosystem. D. In many ecosystems, water is considered a biotic component of the ecosystem.
Chemistry
2 answers:
icang [17]3 years ago
8 0
The answer is...
<span>B. Animals are always biotic components of an ecosystem. 

Explanation...
</span>The living components<span> of the environment are known as </span>biotic factors<span>. </span>Biotic factors<span> include plants, </span>animals<span>, and micro-organisms.</span>
Alexeev081 [22]3 years ago
7 0

Answer: Animals are always biotic components of an ecosystem.

Explanation:

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Under which conditions of temperature and pressure would a 1-liter sample of a real gas behave most like an ideal gas?
Sladkaya [172]

Answer : The correct option is (3) 500 K and 0.1 atm.

Explanation :

A real gas behaves ideally at high temperature and low pressure.

The ideal gas equation is,

PV=nRT

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P = pressure of gas

V = Volume of gas

R = Gas constant

T = temperature of gas

n = number of moles of gas

The ideal gas works properly when the inter-molecular interactions between the gas molecules and volume of gas molecule will be negligible. This is possible when pressure is low and temperature is high.

Therefore, the correct option is (3) 500 K and 0.1 atm.

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2 years ago
What is the composition, in atom percent, of an alloy that contains a) 45.5 lbm of silver, b) 83.7 lbm of gold, and c) 6.3 lbm o
lyudmila [28]

Answer:

\% atAg=44.6\%\\\% atAu=44.9\%\\\% atCu=10.5\%

Explanation:

Hello,

In this case, for computing the atom percent, one must obtain the number of atoms of silver, gold and copper as shown below:

atomsAg=45.5lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{107.87gAg}*\frac{6.022x10^{23}atomsAg}{1molAg}=1.15x10^{26}atomsAg\\atomsAu=83.7lbm*\frac{453.59g}{1lbm}*\frac{1molAu}{196.97gAu}*\frac{6.022x10^{23}atomsAu}{1molAu}=1.16x10^{26}atomsAu\\atomsCu=6.3lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{63.55gCu}*\frac{6.022x10^{23}atomsCu}{1molCu}=2.71x10^{25}atomsCu

Thus, the atom percent turns out:

\% atAg=\frac{1.15x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.6\%\\\% atAu=\frac{1.16x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.9\%\\\% atCu=\frac{2.71x10^{25}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =10.5\%

Best regards.

4 0
3 years ago
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