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kumpel [21]
3 years ago
8

Which of the following statements is true? A. Some plants are considered abiotic components of an ecosystem. B. Animals are alwa

ys biotic components of an ecosystem. C. Temperature range is always a biotic component of an ecosystem. D. In many ecosystems, water is considered a biotic component of the ecosystem.
Chemistry
2 answers:
icang [17]3 years ago
8 0
The answer is...
<span>B. Animals are always biotic components of an ecosystem. 

Explanation...
</span>The living components<span> of the environment are known as </span>biotic factors<span>. </span>Biotic factors<span> include plants, </span>animals<span>, and micro-organisms.</span>
Alexeev081 [22]3 years ago
7 0

Answer: Animals are always biotic components of an ecosystem.

Explanation:

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The density of a sample of F2(g) is 1.559 g/L. If the gas is held at 755 torr, calculate the temperature.
4vir4ik [10]

Answer:

The temperature is 590,10 K

Explanation:

As stated, we understand that there is one mole of F2, which is equivalent to 37.9968x2 grams = 75.936 grams. The unit of Torr is converted to atm, 1 Torr = 0.0013 atm, and with the data of grams it is converted into volume through density:

density = m / v ---> v = m / density = 75,936 g / 1,559 g / l = 48, 708 l

Exactly the formula PV = nRT

n = number of moles (according to what is interpreted in the sentence is 1 mole)

P = pressure 755 Torr (converted to atm 755Torr / 0.0013 atm / Torr = 0.99344 atm)

R = value constant 0.082 l x atm / K x mol

T = is our mystery (in degrees Kelvin)

0.99344 x 48, 708 l = 1 mol x 0.082 l x atm / K x mol x X

X = 0.99344 x 48, 708 l / 1 mol x 0.082 l x atm / K x mol

X = 590, 10 K

The temperature is 590.10 K

7 0
3 years ago
2. A 100.00 mL volumetric flask is loaded with 1.60 grams of NaF. To this was added 30.0 mL of a 4.00 M solution of HF. When thi
Zina [86]

Answer:

pH of the final solution = 3.8

Explanation:

Concentration of NaF = \frac{1.6 X 1000}{42 X 100} molar

                                    = 0.3 molar

NaF → Na⁺ +    F⁻

HF   ⇆ H⁺    +    F⁻

  • NaF is strong electrolyte so completely ionized but HF weak acid not completely ionized.
  • Since F⁻ is common ion here

         according to common ion effect dissociation of weak acid decreases.

        Ka = \frac{[H]^{+}[F]^{-}  }{[HF]}

⇒    [H⁺]  = \frac{K_{a} [HF]}{[F]^{-} } ...............(1)

{Ka of HF = 3.5 x 10⁻⁴} & Concentration of HF = 30 x 4 x 10⁻³ = 0.12 molar

from equation 1

⇒ [H⁺]  = \frac{3.5 X 10^{-4}X 0.12 }{0.3}     [Concentration of F⁻ ≡ Concentration of NaF]

⇒ [H⁺] = 0.00014

⇒pH = - log 0.00014 = 3.85

3 0
3 years ago
Study the following two reactions. Select all that apply.
NISA [10]
Its B and D
...............................................................

7 0
3 years ago
Read 2 more answers
Which flows through the other?
vekshin1
Is there a picture, or.
3 0
3 years ago
A sample in the laboratory is found to contain 3.36 grams of hydrogen, 20.00 grams of carbon, and 26.64 grams of oxygen. The mol
KonstantinChe [14]

Answer:

Empirical formula is CH₂O.

Molecular formula = C₆H₁₂O₆

Explanation:

Given data:

Mass of hydrogen = 3.36 g

Mass of carbon = 20.00 g

Mass of oxygen = 26.64 g

Molar mass of compound = 180.156 g/mol

Empirical formula = ?

Molecular formula = ?

Solution:

Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number

Number of gram atoms of H = 3.36 / 1.01 = 3.3

Number of gram atoms of O = 26.64 / 16 = 1.7

Number of gram atoms of C = 20 / 12 = 1.7

Atomic ratio:

            C                      :        H            :         O

           1.7/1.7                :     3.3/1.7       :       1.7/1.7

              1                     :           2          :        1

C : H : O = 1 : 2 : 1

Empirical formula is CH₂O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass = CH₂O = 12×1 + 2× + 16

Empirical formula mass = 30

n = 180.156 / 30

n = 6

Molecular formula = n (empirical formula)

Molecular formula = 6 (CH₂O)

Molecular formula = C₆H₁₂O₆

5 0
3 years ago
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