Mars has a mass of 642,000,000,000,000,000,000,000 kg. How would
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Answer:
4, 3 , 2 and 6
Explanation:
The reaction equation is given as;
NH₃ + O₂ → N₂ + H₂O
Now, we need to balance the reaction equation;
NH₃ + O₂ → N₂ + H₂O
put the numbers a,b,c and d;
aNH₃ + bO₂ → cN₂ + dH₂O
We need to balance the equation algebraically, ;
Conserving N;
a = 2c
Conserving H;
3a = 2d
Conserving O;
2b = d
Now, let c = 1, a = 2, d = 3 and b =
multiply through by 2;
a = 4, b = 3, c = 2 and d = 6
Insert the parameters:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
Answer:
1) Minimum mass of methane required to heat 45.0 g of water by 21.0°C is 0.0788 g.
2) Minimum mass of methane required to heat 50.0 g of water by 26.0°C is 0.108 g.
Explanation:
1) Minimum mass of methane required to raise the temperature of water by 21.0°C.
Mass of water = m = 45.0 g
Specific heat capacity of water = c = 4.18 J/g°C
Change in temperature of water = ΔT = 21.0°C.
Heat required to raise the temperature of water by 21.0°C = Q
Q = 3,950.1 J = 3.9501 kJ
According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.
Then 3.950.1 kJ of heat will be given by:
Mass of 0.004923 moles of methane :
0.004923 mol × 16 g/mol=0.0788 g
Minimum mass of methane required to heat 45.0 g of water by 21.0°C is 0.0788 g.
2) Minimum mass of methane required to raise the temperature of water by 26.0°C.
Mass of water = m = 50.0 g
Specific heat capacity of water = c = 4.18 J/g°C
Change in temperature of water = ΔT = 26.0°C.
Heat required to raise the temperature of water by 21.0°C = Q
Q = 5,434 J= 5.434 kJ
According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.
Then 5.434 kJ of heat will be given by:
Mass of 0.006773 moles of methane :
0.006773 mol × 16 g/mol= 0.108 g
Minimum mass of methane required to heat 50.0 g of water by 26.0°C is 0.108 g.