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ale4655 [162]
3 years ago
11

Please Help! Thank You

Chemistry
1 answer:
Butoxors [25]3 years ago
5 0

Answer:

61.5 dry quarts = 67.72509L

Explanation:

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Whitney's lung capacity was measured as 3.3 l at a body temperature of 37 ∘c and a pressure of 746 mmhg . how many moles of oxyg
myrzilka [38]

the ideal gas equation is PV=nRT  
 where P=pressure  
 V=Volume  
 n=no. of moles  
 R=universal gas constant  
 T=temperature  
 The universal gas constant (R) is 0.0821 L*atm/mol*K    
 a pressure of 746 mmhg =0.98 atm= 1 atm (approx)   
 T=37 degrees Celsius =37+273=310 K (convert it to Kelvin by adding 273)    
 V=0.7 L (only getting oxygen, get 21% of 3.3L)    
 Solution:  
 (1 atm)(0.7 L)=n(0.0821 L*atm/mol*K)(310 K)  
 0.7 L*atm=n(25.451 L*atm/mol)  
 n=0.0275 mole   
 Answer:   
n=0.0275 mole of oxygen in the lungs.
4 0
3 years ago
A sample of pure NH4HS is placed in a sealed 2.0-L container and heated to 550 K at which the equilibrium constant is 3.5 x 10-3
Zolol [24]

Answer:

The mass of NH_{3} in the container is 2.074 gram

Explanation:

Given:

Volume of NH_{4} HS    V = 2 lit

Equilibrium constant k _{eq} = 3.5 \times 10^{-3}

The reaction in which NH_{3} is produced

  NH_{4} HS ⇄ NH_{3} + H_{2}S

Here equal moles of NH_{3} and H_{2}S is formed.

From the formula of equilibrium constant,

  k_{eq} = (NH_{3})(H_{2}S )

   x^{2} = 3.5 \times 10^{-3}

     x = 0.061 M

Above value shows,

   NH_{3} = 0.061 \frac{moles}{L}

So in 2 L no. moles of NH_{3} = 0.061 \times 2 = 0.122 moles.

So mass of 0.122 mole of NH_{3} is = 0.122 \times 17 = 2.074 g

Therefore, the mass of NH_{3} in the container is 2.074 gram

8 0
3 years ago
Heat required to raise 1 g of a substance 1°C
Oksana_A [137]

Answer:

Specific heat

Explanation:

7 0
3 years ago
What are the physical properties of toothpaste
bogdanovich [222]
The whitening toothpastes showed differences in their physical-chemical properties. All toothpastes promoted changes to the surface, probably by the use of a bleaching agent.
5 0
4 years ago
35.2 J of heat is
ruslelena [56]

The specific heat : c = 0.306 J/g K

<h3>Further explanation</h3>

Given

Heat = 35.2 J

Mass = 16 g

Temperature difference : 7.2 K =

Required

The specific heat

Solution

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

Input the value :

c = Q / m.∆T  

c = 35.2 / 16 x 7.2

c = 0.306 J/g K

7 0
3 years ago
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