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Licemer1 [7]
3 years ago
13

Why nitro group is called an ambident group?​

Chemistry
2 answers:
Zanzabum3 years ago
7 0

Answer:

The nitro group is an ambident group and is capable of getting attached to carbon chain through nitrogen. as well as through oxygen (-O - N = O) atom. The compound in which the -NO2 group is linked to the alkyl or aryl group through oxygen atom are called nitrites

podryga [215]3 years ago
4 0

Answer:

It can bond through either the N or O atoms  

Explanation:

An ambident ("both teeth") group is a group that can attach to another by either of two atoms.

A nitro group can bond through either N or O.

Organic chemistry

In organic chemistry, this property gives rise to functional group isomers.

For example, we can have either nitromethane (CH₃NO₂, Fig. 1) or methyl nitrite (CH₃ONO, Fig. 2)

Inorganic chemistry

The ambidentate property of the nitro group gives rise to linkage isomers in inorganic coordination complexes.

For example, we can have either a pentachloronitroiron(III) cation (Fig. 3) or a pentachloronitritoiron(III) cation (Fig. 4)

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Answer:

k = [F2]² [PO]² / [P2] [F2O]²

Explanation:

In a chemical equilibrium, the equilibrium constant expression is written as the ratio between the molar concentration of the products over the molar concentration of the reactants. Each species powered to its reaction coefficient. For the equilibrium:

P2(g) + 2F2O(g) ⇄ 2PO(g) + 2F2(g)

The equilibrium constant, k, is:

k = [F2]² [PO]² / [P2] [F2O]²

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Why are covalent bonds between hydrogen and nitrogen or oxygen polar? see section 2.1 ( page 57) ?
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The answer for the following problem is mentioned below.

  • <u><em>Therefore the final volume of the gas is 52.7 ml.</em></u>

Explanation:

Given:

Initial pressure (P_{1}) = 290 kPa

Final pressure (P_{2}) = 104 kPa

Initial volume (V_{1}) = 18.9 ml

To find:

Final volume (V_{2})

We know;

From the ideal gas equation;

    P × V = n × R × T

where;

P represents the pressure of the gas

V represents the volume of gas

n represents the no of the moles

R represents the universal gas constant

T represents the temperature of the gas

So;

   P × V = constant

   P ∝ \frac{1}{V}

From the above equation;

              \frac{P_{1} }{P_{2} }  = \frac{V_{2} }{V_{1} }

P_{1} represents the initial pressure of the gas

P_{2} represents the final pressure of the gas

V_{1} represents the initial volume of the gas

V_{2} represents the final volume of the gas

Substituting the values of the above equation;

                    \frac{290}{104} = \frac{V_{2} }{18.9}

             V_{2} = 52.7 ml

<u><em>Therefore the final volume of the gas is 52.7 ml.</em></u>

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3 years ago
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