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vladimir1956 [14]
4 years ago
14

The conversion of co2 and h2o into organic compounds using energy from light is called what?your answer

Chemistry
1 answer:
AlexFokin [52]4 years ago
6 0
Wouldn't that be photosynthesis?
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How many moles are equal to 4.15x10^23 molecules of carbon monoxide?
Rudiy27
To be able to determine the number of moles that a certain number of molecules comprises, we simply divide the number of molecules by the Avogadro's number which is equal to 6.022 x 10^23. 

   n = M/A

where n is the number of moles, M is the number of molecules, and A is Avogadro's number. Substituting the known values,

   n = (4.15 x 10^23 molecules)/(6.022 x 10^23 molecules/mol)

Simplifying,
  
   n = 0.689 moles

<em>Answer: 0.689 moles</em>

7 0
3 years ago
Read 2 more answers
Which of the following statements describe what a normative system is?​
natta225 [31]

Explanation:

though the statements were not given let just give you a brief review of normative system.

A normative statement explains what should be base of the subject according to the belief through valued judgement that describes the fairness of the subject on public policy. Therefore, the unemployment rate should be lowered is a valued judgement based on the belief that it will bring economic welfare.

Normative systems, i.e., sets of norms, have two main. tions: a) to evaluate human actions, and b) to guide peop. The guidance and the evaluation based on a normativ. be good or bad.In social psychology three different normative behaviours have been identified: obedience, conformity and compliance.In the context of a normative system like law (or religion or morality), every statement of what one ought to do (or ought not to do) requires justification from a more general or basic statement. Such statements lead upward through the normative hierarchy until one reaches a foundational normative premise.

please rate brainliest if helps and follow

4 0
2 years ago
Identify each energy exchange as primarily heat or work and determine whether the sign of ΔE is positive or negative for the sys
Semmy [17]

Answer:

a. Work, ΔE is negative;

b. Work, ΔE is negative;

c. Work, ΔE is positive.

Explanation:

In the three cases, there is energy exchange in primarily work. The heat is the energy flow because of the difference in temperature. Of course, some heat may be lost in the cases by dissipation.

In the letter <em>a</em> the system is at an initial velocity different from 0, and then it stops. The energy that is represented here is the kinetic energy, which is the energy of the movement. Note that the system goes from a higher velocity to 0, so it is losing kinetic energy, or work, so ΔE = Efinal - Einitial < 0.

In letter <em>b</em>, the system is falling from a certain high to the floor, so its gravitational potential energy is change. That potential energy represents the energy that gravity does when an object shifts vertically. Because it goes from a high to 0, the energy is been lost, so ΔE = Efinal - Einitial < 0.

In letter <em>c</em>, the system is going higher and with higher velocity, so there is a greatness in the gravitational potential energy and the kinetic energy, both works, so ΔE = Efinal - Einitial > 0.

8 0
4 years ago
Someone know how to solve for moles of ions??? URGENT!!!
melamori03 [73]

Answer = 4.5


Rationale:

the element Mg comes with a 2+ ion and NO3 comes with -1 ion thus 3 * 1.5 M = 4.5 basically look up what mg ion is on google and it says mg+2 and no3 ion no3- im assuming you cant though so look at the formula.


Mg(NO3)2, mg gave 2 to NO3 but where is mg's number? its 1 so 2+1 = 3

* # M = ans


6 0
4 years ago
Give the value of the quantum number ℓ, if one exists, for a hydrogen atom whose orbital angular momentum has a magnitude of 6√(
MakcuM [25]

Answer:

For this angular momentum, no quantum number exist

Explanation:

From the question we are told that

   The magnitude of the angular momentum is  L  = 6\sqrt{\frac{h}{2 \pi} }

The generally formula for Orbital angular momentum is mathematically represented as

           L  = \sqrt{(l * (l + 1)) } *  \frac{h}{2 \pi}

Where l is the quantum number

now  

We can look at the given angular momentum in this form as

      L  = 6\sqrt{\frac{h}{2 \pi} }    =  \sqrt{36}  * \sqrt{\frac{h}{2 \pi}} }

comparing this equation to the generally equation for Orbital angular momentum

     We see that there is no quantum number that would satisfy this equation

5 0
4 years ago
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