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viva [34]
4 years ago
5

Running up a hill instead of a flat surface will increase which principle of fitness?

Physics
2 answers:
4vir4ik [10]4 years ago
7 0

Answer:

im pretty sure its intensity

Explanation:

musickatia [10]4 years ago
5 0

Answer:

a

Explanation:

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How many forces are acting on a stationary raft floating in a swimming pool A1 B2 or C3
Hitman42 [59]
There are at least two forces on it, and there could be more.

Vertical forces:
-- gravity, directed downward
-- buoyant force, directed upward
These two forces must be exactly equal, so that the net
vertical force on the raft is zero.  Otherwise, it would be
accelerating either up or down.

Horizontal forces:
We know that the net horizontal force on the raft is zero. 
Otherwise, it would be accelerating horizontally.

But we don't know if there are actually no horizontal forces
at all, or a balanced group of horizontal forces, that add up
to a net force of zero.
3 0
3 years ago
If a current of 2.0 A is flowing from point a to point b, the potential difference between Vb- Va (in V) is:
Aliun [14]

Answer:

\huge\color{skyblue}\boxed{\colorbox{black}{Answer ☘}}

total \: resistance \: ( R_{t} ) = (3 + 1)ohm \\ (since \: the \: resistors \: are \: connected \\ in \: series)

current \: flowing \: through \: circuit(I)  = 2A \\  \\ now... \: by \: ohms \: law \\ V = IR\\ V = (2)(4) \\  =  > 8v

<h3>therefore , option (b) is correct!!</h3>

hope helpful~

5 0
2 years ago
If =12a andthe distance from each wire to point p is 0.12m, then what is the magnitude of the magnetic force per unit length on
vaieri [72.5K]

The magnitude of the magnetic force per unit length on the top wire is

2×10⁻⁵  N/m

<h3>How can we calculate the magnitude of the magnetic force per unit length on the top wire ?</h3>

To calculate the magnitude of the magnetic force per unit length on the top wire, we are using the formula

F= \frac{\mu_0 I_f}{2\pi d}

Here we are given,

\mu_0= magnetic permeability

= 4\pi×10⁻⁷ H m⁻¹

If= 12 A

d= distance from each wire to point.

=0.12m

Now we put the known values in the above equation, we get

F= \frac{\mu_0 I_f}{2\pi d}

Or, F = \frac{4\pi \times 10^{-7}\times  12}{2\pi \times 0.12}

Or, F= 2×10⁻⁵ N/m.

From the above calculation, we can conclude that the magnitude of the magnetic force per unit length on the top wire is 2×10⁻⁵ N/m.

Learn more about magnetic force:

brainly.com/question/2279150

#SPJ4

7 0
2 years ago
A spring scale hung from the ceiling stretches by 6.1 cm when a 2.0 kg mass is hung from it. The 2.0 kg mass is removed and repl
Hunter-Best [27]

The ideal spring equation is

                               Stretch  =  K  times  Force  .

This says that the stretch is directly proportional to the force.
In simple English, that means that if you double the force, then
you double the stretch, and if you multiply the force by  π  or
any other number, you multiply the stretch by the same number.

So you can always write a proportion for a spring:

                 Stretch₁ / Force₁  =  Stretch₂ / Force₂ .

Part A:

In Part-A of this question, the force is increased to  (2.5 / 2.0) =  1.25 times .

So the stretch is also increased to  1.25 times .

                 (1.25) x (6.1 cm)  =  7.625 cm  .
6 0
4 years ago
A force of 7.50 N is applied to a spring whose spring constant is .298 N/cm. Find it’s length
gizmo_the_mogwai [7]

Answer:

to find the length just divide 7.50 and . 298

5 0
3 years ago
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