18 mililiter is equivilent to 0.0047551
Answer:
Malleability
Explanation:
The ability to roll aluminum foil in a ball is the property of metal called malleability.
- Metallic bonds in metals makes it possible for them to take different shape without losing internal cohesion.
- Metals are malleable and they posses a wide range of physical properties.
- A malleable metal can be beaten into sheets and molded into many shapes.
Answer:
4 stroke 4 cylinder Natural Aspirated Gasoline engine
Explanation:
im not 100% sure
We can solve the problem by using conservation of momentum.
The player + ball system is an isolated system (there is no net force on it), therefore the total momentum must be conserved. Assuming the player is initially at rest with the ball, the total initial momentum is zero:

The total final momentum is:

where
is the momentum of the player and
is the momentum of the ball.
The momentum of the ball is: 
While the momentum of the player is:
, where M=59 kg is the player's mass and vp is his velocity. Since momentum must be conserved,

so we can write

and we find

and the negative sign means that it is in the opposite direction of the ball.
1/2*2.8*x^{2}=2.8*9.81*1.50
X=5.425
Because K.E=1/2*M*V² and it is equal to P.E in the conservation of energy which means its K.E=P.E
P.E=m*g*h
So K.E equals 1/2*2.8*(5.425)²=41.20