The frictional force is oposing the force that we apply to this mass. Therefore the overall force is
The second principle of physics tells us that the acceleration of a mass is direct proportional to the applied force, the mass of that object being the proportionality constant.
Hence
The average speed in m/s of a person that jogs eight complete laps around a 400m track in a total time of 15.1 min is 0.44m/s.
<h3>How to calculate average speed?</h3>
Average speed of a moving body can be calculated by dividing the distance moved by the time taken.
Average speed = Distance ÷ time
According to this question, a person jogs eight complete laps around a 400m track in a total time of 15.1 min. The average speed is calculated as follows:
15.1 minutes in seconds is as follows = 906 seconds
Average speed = 400m ÷ 906s
Average speed = 0.44m/s
Therefore, the average speed in m/s of a person that jogs eight complete laps around a 400m track in a total time of 15.1 min is 0.44m/s.
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Answer:
9.4 m/s
Explanation:
According to the work-energy theorem, the work done by external forces on a system is equal to the change in kinetic energy of the system.
Therefore we can write:
where in this case:
W = -36,733 J is the work done by the parachute (negative because it is opposite to the motion)
is the initial kinetic energy of the car
is the final kinetic energy
Solving,
The final kinetic energy of the car can be written as
where
m = 661 kg is its mass
v is its final speed
Solving for v,
Answer:
the answer is at
Explanation:
Dimension of at = [ LT^-2 ] [ T ]
= [ LT^(-2+1) ]
= [ LT^-1 ]
which is same as dimension of speed.
Answer:
The fundamental frequency and length of the pipe are 100 Hz and 1.7 m.
Explanation:
Given that,
Frequency f = 550 Hz
Frequency f' = 650 Hz
We know that,
AMT pipe is open pipe.
(b). We need to calculate the length of the pipe
Using formula of organ pipe
For 550 Hz,
...(I)
For 650 Hz,
...(II)
From equation (I) and (II)
(a). We need to calculate the fundamental frequency for n = 1
Using formula of fundamental frequency
put the value of L
Hence, The fundamental frequency and length of the pipe are 100 Hz and 1.7 m.
