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Delvig [45]
4 years ago
14

An object has 90,000 J of kinetic energy and is moving at 12 m/s. What is the objects mass?

Physics
1 answer:
trapecia [35]4 years ago
4 0

Answer:

plug it into your calculator

Explanation:

Kinetic energy = KE = Joules = J

KE= 1/2mv^2

90,000 = 1/2 m (12^2)

180,000 = m (144)

m = 180,000 / 144

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DIA [1.3K]
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6 0
3 years ago
Read 2 more answers
A truck pushes a pile of dirt horizontally on a frictionless road with a net force of 20\, \text N20N20, start text, N, end text
meriva

Answer:

300 Nm ; 300 J

Explanation:

Given that:

Force (F) = 20 N

Distance (d) = 15 m

The kinetic energy (Workdone) = Force * Distance

Kinetic Energy = 20N * 15m

Kinetic Energy = 300Nm

K. E = 1/2

4 0
3 years ago
Read 2 more answers
Coach Hogue is riding his motorcycle in a circle on wet pavement. Suddenly the bike slides out from under him. What failed to pr
Arisa [49]

Answer:

The correct option is;

Force of Friction

Explanation:

As coach Hogue rode his motorcycle round in circle on the wet pavement, the motorcycle and the coach system tends to move in a straight path but due to intervention by the coach they maintain the circular path

The motion equation is

v = ωr and we have the centripetal acceleration given by

α = ω²r and therefore centripetal  force is then

m×α = m × ω²r = m × v²/r

The force required to keep the coach and the motorcycle system in their circular path can be obtained by the impressed force of friction acting towards the center of the circular motion.

5 0
3 years ago
The radial velocity method preferentially detects: Choose one: A. all of the above described planets equally well. B. small plan
Zina [86]

The radial velocity method preferentially detects large planets close to the central star

  • what is the Radial velocity:

The radial velocity technique is able to detect planets around low-mass stars, such as M-type (red dwarf) stars.

This is due to the fact that low mass stars are more affected by the gravitational tug of planets.

When a planet orbits around a star, the star wobbles a little.

From this, we can determine the mass of the planet and its distance from the star.

hence we can say that,

option D is correct.

The radial velocity method preferentially detects large planets close to the central star

Learn more about radial velocity here:

<u>brainly.com/question/13117597</u>

#SPJ4

5 0
2 years ago
What is the period of a simple pendulum 47 cm long (a) on the Earth, and ( b) when it is in a freely falling elevator?
Liula [17]

Answer:

a)1.37 s

b)∞ ( Infinite)

Explanation:

Given that

L= 47 cm              ( 1 m =100 cm)

L= 0.47 m

a)

On the earth :

Acceleration due to gravity = g

We know that time period of the simple pendulum given as

T=2\pi\sqrt{ \dfrac{L}{g_{{eff}}}

Here

g_{eff}= g

Now by putting the values

T=2\pi \times\sqrt{ \dfrac{0.47}{9.81}}

T=1.37 s

b)

Free falling elevator :

When elevator is falling freely then

g_{eff}= 0            ( This is case of weightless motion)

Therefore

T=2\pi\sqrt{ \dfrac{L}{0}

T=∞  (Infinite)

6 0
4 years ago
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