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3 years ago

Cells are the basic building block that makes up all living things. Cells are microscopic. What does this mean?

Physics

2 answers:

Archy [21]3 years ago

6 0

Answer:

microscopic means that they are very very tiny, you cannot see them with the human eye, you have to use a tool like a microscope

Explanation:

Yuri [45]3 years ago

3 0

All things are made of cells or are a cell, and they are microscopic meaning you can't see them with only the human eye.

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As an airplane leaves the runway and goes into the air, has acceleration occurred?

malfutka [58]

A, yes because the plane is using air resistance and acceleration is increasing while it goes up. Although you don’t know speed, still yes.

6 0

2 years ago

When you speak or sing, you force air through your ?

zaharov [31]

You force air from your lungs up through your larynx which is commonly called the voicebox

6 0

3 years ago

While rearranging a dorm room, a student does 310 J of work in moving a desk 2.9 m. What was the magnitude of the applied horizo

Viefleur [7K]

Answer:

The horizontal force is 106.89 N.

Explanation:

Given that,

Work done = 310 J

Distance = 2.9 m

We need to calculate the horizontal force

Using formula of work done

$W= Fd\cos\theta$

Where, $\theta=0^{\circ}$

$W=F\cdot d$

Put the value into the formula

$310=F\cdot 2.9$

$F=\dfrac{310}{2.9}$

$F=106.89\ N$

Hence, The horizontal force is 106.89 N.

3 0

3 years ago

The specific heat of water is 4.2 J/g • °C. How much heat is required to raise the temperature of 100 g of water by 5°C? *

Svetach [21]

Answer:

2100 J

Explanation:

The heat required to increase the temperature of a substance is given by

$Q=mC\Delta T$

where

m is the mass of the substance

C is its specific heat capacity

$\Delta T$ is its change in temperature

For the water in this problem, we have:

m = 100 g is its mass

C = 4.2 J/g • °C is the specific heat capacity

$\Delta T=5^{\circ}C$ is the increase in temperature

So, the amount of heat needed is:

$Q=(100)(4.2)(5)=2100 J$

7 0

3 years ago

A person walks 30m due north, then 50m at 35 degrees. Find their total displacement.

Harman [31]

Using the cosine rule (a^2 = b^2 + c^2 - 2bc cos A), we can work out the displacement:
Displacement = a
b = 30
c = 50
A = 180 - 35 = 145 degrees.

a^2= 900 + 2500 -1500*-0.81915...
= 3400 + 1228.728...
= 4628.72...
a = 68.034...
= 68.0m (to 3s.f.).

To work out the angle from starting place, use another configuration of the cosine rule:
$cos(C)= \frac{a^{2} +b^{2}- c^{2} }{2ab}$ :
cos (C)= $\frac{4628.72...+900-2500}{2*68*30}$
= 3028.7.../4080
= 0.7423...
C = 42.069... degrees
= 042 bearing

5 0

3 years ago