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BigorU [14]
3 years ago
9

As the temperature of the gas in a balloon decreases which occurs after

Physics
1 answer:
Mariana [72]3 years ago
7 0

Answer:

The Ballon will shrink.

Explanation:

Temperature is the measure of the average kinetic energy of the air molecules within the Ballon. As the temperature is gradually reduced, the molecules lose kinetic energy and their movement around the Ballon reduces which reduces the rate at which they collide with the Ballon walls. As the temperature drops further, the molecules comes even more closer since they can't move around any further causing the Ballon to shrink.

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A baseball is hit into the air with a velocity of 27 m/s. How high does it go?
Marizza181 [45]

Answer:

Explanation:

If a baseball is hit into the air with a velocity of 27 m/s, we want to determine the maximum height of the ball. Using the projecile formula;

Max height H = u²/2g

u is the initial velocity of the body = 27m/s

g is the acceleration due to gravity = 9.81m/s²

H = 27²/2(9.81)

H = 729/19.62

H = 37.16m

Hence the ball went 37.16m high

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3 years ago
A white billiard ball with mass mw = 1.37 kg is moving directly to the right with a speed of v = 3.14 m/s and collides elastical
Ira Lisetskai [31]

That latest value for the Angle is in Grads, not in Kilograms.

Apply law of conservation of momentum along vertical direction.

m_1v_1sin\theta_1-m_2v_2sin\theta_2=0

v_2=\frac{v_1sin\theta_1}{sin\theta_2}=\frac{sin54}{sin36}v_1 = 1.376v_1

Apply law of conservation of momentum along the horizontal direction

m_1u_1=m_1v_1cos\theta_1+m_2v_2cos\theta_2

u_1=v_1(cos\theta_1+1.376cos\theta_2)

u_1=v_1(cos(54)+1.376cos(36))

u_1=(1.7) v_1

v_1= \frac{3.14}{1.7}=1.84m/s

The second ball velocity is v_2 = (1.376)(1.84)=2.531m/s

The magnitud of final total momentum is

m(v_1+v_2)=(1.37)(2.531+1.84)=5.98kgm/s

The magnitude of final energy is

\frac{1}{2}m(v^2_1+v^2_2)=\frac{1}{2}(1.37)(2.531^2+1.84^2)=6.07J

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3 years ago
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