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3 years ago

As the temperature of the gas in a balloon decreases which occurs after

Physics

1 answer:

Mariana [72]3 years ago

7 0

Answer:

The Ballon will shrink.

Explanation:

Temperature is the measure of the average kinetic energy of the air molecules within the Ballon. As the temperature is gradually reduced, the molecules lose kinetic energy and their movement around the Ballon reduces which reduces the rate at which they collide with the Ballon walls. As the temperature drops further, the molecules comes even more closer since they can't move around any further causing the Ballon to shrink.

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An electric field around two charged objects is shown.

mamaluj [8]

Answer: D

<u></u>

X: positive

Y: negative

Explanation:

It's either A or D and I chose A and got it wrong.

3 0

3 years ago

Using the formula 1/2 (m x v2), what is the kinetic energy of a 4 kg rock falling through the air at 5 m/s

aivan3 [116]

Answer:

KE = 50J

Explanation:

$KE = \frac{1}{2}mv^{2} \\\\ KE = \frac{1}{2}(4)(5)^{2} \\\\ KE = 2(25) \\\\ KE = 50J$

5 0

3 years ago

In this graph, what is the displacement of the particle in the last two seconds?

nikklg [1K]

In this graph, what is the displacement of the particle in the last two seconds?of the particle in the last two seconds?

<span>0.2 meters
2 meters
4 meters
6 meters</span>
In this graph, the displacement of the particle in the last two seconds is 2 meters.

7 0

3 years ago

The resistivity of gold is at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a current of 940 m

IgorC [24]

Answer:

0.0360531138247 V/m

Explanation:

$\rho$ = Resistivity of gold = $2.44\times 10^{-8}\ \Omega .m$ (General value)

I = Current = 940 mA

d = Diameter = 0.9 mm

A = Area = $\dfrac{\pi}{4}d^2$

E = Electric field

Resistivity is given by

$\rho=\dfrac{EA}{I}\\\Rightarrow E=\dfrac{\rho I}{A}\\\Rightarrow E=\dfrac{2.44\times 10^{-8}\times 940\times 10^{-3}}{\dfrac{\pi}{4}(0.9\times 10^{-3})^2}\\\Rightarrow E=0.0360531138247\ V/m$

The electric field in the wire is 0.0360531138247 V/m

6 0

3 years ago

Read 2 more answers

Suppose astronomers discover a type-M star with a very large luminosity. What type of star is it likely to be

lianna [129]

Answer: A red supergiant

Explanation:

Red supergiants are the stars that have a supergiant luminosity which has a class of either K or M spectral type. In terms of volume, they are regarded as the largest stars on Earth even though they are not the most luminous.

Red supergiants are formed when a star collapses after the hydrogen fuel that the star has in its core runs out and

then fusion begins when the outer shells of hydrogen gets hot.

8 0

3 years ago