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andreyandreev [35.5K]
2 years ago
7

Difference between combustible and non - combustible

Chemistry
2 answers:
shtirl [24]2 years ago
7 0

Answer:

A substance which burns in air and tends to produce heat and light is known as Combustible substances. Non-combustible substances are certain substances which are not combustible in the presence of air. Will not burn on being exposed to flame.

Oxana [17]2 years ago
3 0

Answer:

A substance which burns in air and tends to produce heat and light is known as Combustible substances. Non-combustible substances are certain substances which are not combustible in the presence of air. Will not burn on being exposed to flame.

Explanation:

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What is the ph of a 4.8 m pyridine solution that has kb = 1.9 × 10-9? the equation for the dissociation of pyridine is?
Eddi Din [679]

Answer: 9.98


Explanation:


1) The equation for the dissociation of pyridine is:


C₅H₅N₅(aq )+ H₂O(l) ⇄ C₅H₅NH⁺(aq) + OH⁻(aq)


2) Kb equation:


Kb = [C₅H₅NH⁺(aq)] [OH⁻(aq)] / [C₅H₅N₅(aq )]


Where:


[C₅H₅NH⁺(aq)] = [OH⁻(aq)] ← from the equilibrium reaction


[C₅H₅N₅(aq )] = 4.8 M ← from the statement


⇒ 1.9 × 10 ⁻⁹ = x² / 4.8 ⇒ x² = 9.12 × 10⁻⁹


⇒ x = 9.55 × 10⁻⁵ = [OH⁻(aq)]


3) pOH


pOH = - log [OH⁻(aq)] = 4.02


4) pOH + pH = 14


⇒ pH = 14 - 4.02 = 9.98

4 0
2 years ago
Read 2 more answers
What is the actual amount of phosphorous in a fertilizer with a NPK ratio of 15-15-20?
natulia [17]
I believe it’s 17 or 18
4 0
3 years ago
Emission nebulae are also called ____ because they are composed of ionized hydrogen.
vodomira [7]
H II regions. The ionized gas emits various colors of light and creates some of the most beautiful formations in the observable universe. These are slo regions where star formation is often taking plan and young stars are being formed from the remnants of older stars. 
8 0
2 years ago
What is the volume of an object whose dimensions are 5.54 cm, 10.6 cm, and 199 cm? Round your answer to the correct number of si
Akimi4 [234]

Answer:

D. 11686.076 cm^3.

Explanation:

Assuming that this is a prism the volume is:

5.54 * 10.6 * 199

= 11686.076 cm^3.

8 0
2 years ago
A 20.0-milliliter sample of 0.200 M K2CO3 solution is added to 30.0 milliliters of 0.400 M Ba(NO3)2 solution.
jenyasd209 [6]

Answer:

(B) 0.160 M

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For K_2CO_3 :

Molarity = 0.200 M

Volume = 20.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 20.0×10⁻³ L

Thus, moles of K_2CO_3 :

Moles=0.200 \times {20.0\times 10^{-3}}\ moles

Moles of K_2CO_3 = 0.004 moles

For Ba(NO_3)_2 :

Molarity = 0.400 M

Volume = 30.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume =30.0×10⁻³ L

Thus, moles of Ba(NO_3)_2 :

Moles=0.400\times {30.0\times 10^{-3}}\ moles

Moles of Ba(NO_3)_2  = 0.012 moles

According to the given reaction:

K_2CO_3_{(aq)}+Ba(NO_3)_2_{(aq)}\rightarrow BaCO_3_{(s)}+2KNO_3_{(aq)}

1 mole of potassium carbonate react with 1 mole of barium nitrate

0.004 moles potassium carbonate react with 0.004 mole of barium nitrate

Moles of barium nitrate  = 0.004 moles

Available moles of barium nitrate  =  0.012 moles

Limiting reagent is the one which is present in small amount. Thus, potassium carbonate is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of potassium carbonate gives 1 mole of barium carbonate

Also,

0.004 mole of potassium carbonate gives 0.004 mole of barium carbonate

Mole of barium carbonate = 0.004 moles

Also, consumed barium nitrate = 0.004 moles  (barium ions precipitate with carbonate ions)

Left over moles = 0.012 - 0.004 moles = 0.008 moles

Total volume = 20.0 + 30.0 mL = 50.0 mL = 0.05 L

So, Concentration = 0.008/0.05 M = 0.160 M

<u>(B) is correct.</u>

4 0
3 years ago
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