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Xelga [282]
3 years ago
13

What is the rarefraction of a longitude wave

Chemistry
1 answer:
kvv77 [185]3 years ago
5 0

Answer:

it is a transverse wave. Does that help?

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Choose the products that complete the reaction. The chemical equation may not be balanced.
Alina [70]

Al2(SO4)3 + H2

Explanation:

8 0
3 years ago
Read 2 more answers
HELP ASAP 50-50 CHANCE
docker41 [41]

Answer: The answer is A, A new element or different atom formed from the original two.

Hope this helps! :D

-<em>TanqR</em>

4 0
3 years ago
Does volume alone determine whether an object will sink or float? Explain.
Bond [772]

Answer:

no.

Density (mass / volume) determines whether an object floats or sinks. If the object is less dense than the medium in which it has been submerged, it floats. if it is more dense, it sinks. Volume will definitely determine if a steel ship floats, as steel is far more dense than water.

#FreeMelvin

3 0
3 years ago
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How many grams of ammonia must you start with to make 900.00 l of a 0.140 m aqueous solution of nitric acid? assume all the reac
bogdanovich [222]
You need the set of reactions that goes from ammonia to nitric acid.
<span>
1) 4NH3(g)+5O2(g)-->4NO(g)+6H2O(g)

2) 2NO(g)+O2(g)-->2NO2(g)

3) 3NO2(g)+H2O(l)-->2HNO3(aq)+NO(g)

State the ratio of moles of HNO3 to NH3:

4 moles of NH3 produce 4 mole of NO,

4 moles of NO produce 4 moles of NO2

4 moles of NO2 produce 4 * (2 / 3) moles of HNO3 = 8/3 moles of HNO3.

=> (8/3) moles HNO3 : 4 moles NH3

Calculate the number of moles of HNO3 in 900.00 l of 0.140 M solution

M = n / V => n = M * V = 0.140 M * 900.00 liter = 126 moles HNO3

Use proportions:

(</span><span>8/3) moles HNO3 / 4 moles NH3 = 126 moles HNO3 / x

=> x = 126 moles HNO3 * 4 moles NH3 / (8/3 moles HNO3) = 189 moles NH3

Convert moles to grams:

molar mass NH3 = 14 g/mol + 3 * 1g/mol = 17 g/mol

mass in grams = number of moles * molar mass = 189 moles * 17 g/mol = 3213 g

Answer: 3213 g.
</span>
3 0
3 years ago
It takes 330 joules of energy to raise the temperature of 24.6 gbenzene from 21 degrees Celsius to 28.7 degrees Celsius at const
lilavasa [31]

Given :

Energy , E = 330 J .

Initial temperature , T_i=21^oC .

Final temperature , T_f=24.6^oC .

Mass of benzene , m = 24.6 g .

To Find :

The molar hear capacity of benzene at constant pressure .

Solution :

Molecular mass of benzene , M = 78 g/mol .

Number of moles of benzene :

n=\dfrac{24.6}{78} \ mol\\\\n=0.32 \ mol

Energy required is given by :

q=nC_p\Delta T\\\\330=0.32\times C_p\times (28.7-21)\\\\C_p=\dfrac{330}{0.32\times 7.7}\ J\ mol^{-1}^oC^{-1} \\\\C_p=133.9\ J\ mol^{-1}^oC^{-1}

Hence , this is the required solution .

8 0
3 years ago
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