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Butoxors [25]
3 years ago
6

The owner of a van installs a rear-window lens that has a focal length of -0.298 m. When the owner looks out through the lens at

a person standing directly behind the van, the person appears to be just 0.245 m from the back of the van, and appears to be 0.338 m tall. (a) How far from the van is the object actually located, and (b) how tall is the object?
Physics
1 answer:
Montano1993 [528]3 years ago
6 0

Answer:

a) 1.376 m

b) 1.899 m

Explanation:

Given

Focal length of the lens, f = -0.298 m

Distance of the image, d(i) = 0.245 m

Size of the image, I = 0.338 m

Using the following connotations,

O = object size

do = object distance

I = image size

di = image distance

f = focal length

The owner has a concave lens.

The magnification of this lens is I/O = (-f + di)/-f

I/O = (0.298 - 0.245)/0.298 =

I/O = 0.053 / 0.298

I/O = 0.178

Also,

I/O = -di/do, so that

I/O = 0.178 = -di/do

do = 0.245/0.178 = 1.376 m (distance of person from rear of car.

O = I/0.178

O = 0.338/0.178

O = 1.899 m (size of person)

Therefore, the distance of the object from the van is 1.376 m and the size of the object is 1.899 m

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Does the air exert a buoyant force on all objects in air or only on objects such as balloons that are very light for their size?
Citrus2011 [14]

Answer:

See explanation

Explanation:

Solution:-

Buoyancy is the force that causes objects to float. It is the force exerted on an object that is partly or wholly immersed in a fluid. Buoyancy is caused by the differences in pressure acting on opposite sides of an object immersed in a static fluid. It is also known as the buoyant force. Buoyancy is the phenomena due to Buoyant Force.

It is as an upward force exerted by a fluid that opposes the weight of an object immersed in a fluid. As we know, the pressure in a fluid column increases with depth. Thus, the pressure at the bottom of an object submerged in the fluid is greater than that at the top. The difference in this pressure results in a net upward force on the object which we define as buoyancy.

- The formula for buoyant force (Fb) is given:

                           Fb = ρ*g*V

- The force acts on all objects. However, it depends on the fluid density and amount of volume displaced.

- The Buoyant force exerted by air with density = 1.225 kg/m^3 on an object with volume (V) is:

                          Fb = ρ*g*V = 1.225*9.81*V = 12.02*V

- For the similar object with mass (m), the downward weight would be:

                           W = m*g

- For the object to float the buoyant force (Fb) must be greater than weight of the object:

                          Fb > W

                          12.02*V > m*9.81

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6 0
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I need help with this physics question
OlgaM077 [116]

Answer:

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Read 2 more answers
A camera operator is filming a nature explorer in the Rocky Mountains. The explorer needs to swim across a river to his campsite
julia-pushkina [17]

Answer:

<em>a. Angle= 28.82°</em>

<em>b. Approved. He will get cold but he should be able to make it across</em>

Explanation:

Velocity Vector

The velocity is a physical quantity that measures how fast or slow at a particular direction some object is moving. It must be expressed as a vector with both a magnitude and direction. If the object is confined to move in one direction, then we can use the speed as the scalar (magnitude only) equivalent of the velocity.

a.

The explorer wants to swim across a river to his campsite, as shown in the image below. The river has a velocity vr and the explorer can swim at ve in still water. If he swam directly to the campsite, he would end up in a point below it because the river would push him down. He must swim with a velocity such that he overcomes the stream but he advances to its objective. Let's call the angle he must swim at respect to the shoreline to achieve his goal. The explorer's velocity can be decomposed in its rectangular components vx and vy. To overcome the river's velocity:

v_{ey}=v_r

We can compute the vertical component of the explorer's velocity as

v_{ey}=|v_e|cos\alpha

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v_r=|v_e|cos\alpha

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\displaystyle cos\alpha=\frac{v_r}{|v_e|}

\displaystyle cos\alpha=\frac{0.665}{0.759}=0.876

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\alpha=28.82^o

b.

The horizontal component of the explorer's velocity is

v_{ex}=0.759sin28.82^o

v_{ex}=0.366\ m/s

This is the real velocity the explorer is having directly to the campsite

Knowing that

\displaystyle v=\frac{x}{t}

Solving for t

\displaystyle t=\frac{x}{v}

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\displaystyle t=\frac{29.3}{0.366}

t=80\ sec

Since this value is less than the limit value of hypothermia (300 sec), the decision is

Approved. He will get cold but he should be able to make it across

3 0
3 years ago
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