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jarptica [38.1K]
3 years ago
10

A mass of mercury occupies 0.750 L. What volume would an equal mass of ethanol occupy? The density of mercury is 13.546 g/mL, an

d the density of ethanol is 0.789 g/mL.
Physics
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

Ve=12876.43mL  : Ethanol volume

Explanation:

We apply the formula to calculate the density:

ρ=\frac{m}{V} Formula (1)

Where:

ρ:Density in g/mL

m: mass in g (grams)

V= Volume in ml (milliliters)

We know the following data:

1L= 1000mL

Vm=Volume of mercury:VHg=0.750 L*1000mL/L=750mL

ρ-m=Density of mercury =13.546 g/mL

ρ-e: density of ethanol is 0.789 g/mL

m_{m} =m_{e}

Development of the problem:

In formula 1 We replace the known data for the  mercury :

ρ-m=\frac{m_{m} }{V_{m} }

13.546 \frac{g}{mL} =\frac{m_{m} }{750mL}

m_{m}=13.546 \frac{g}{mL}*750mL

m_{m} =10159.5 g

We know that m_{e} =m_{m} =10159.5 g, then, We replace the known data for the  ethanol In formula 1:

ρ-e=\frac{m_{e} }{V_{e} }

0.789 \frac{g}{mL} =\frac{10159.5g}{V_{e} }

Ve=\frac{10159.5 g}{0.789 \frac{g}{mL}}

Ve=12876.43mL

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3 years ago
A bodybuilder deadlifts a 215 kg weight to a height of 0.90 m above the ground. If he deadlifts this weight 10 times in a span o
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A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)

<h3>What is power?</h3>

In physics, power (P) is the work (W) done over a period of time.

  • Step 1. Calculate the work done by the bodybuilder each time.

The bodybuilder lifts a 215 kg (m) weight to a height of 0.90 m (h). Being the gravity (g) of 9.81 m/s², we can calculate the work done in each lift using the following expression.

W = m × g × h = 215 kg × 9.81 m/s² × 0.90 m = 1.9 × 10³ N

  • Step 2. Calculate the work done by the bodybuilder over 10 times.

W = 10 × 1.9 × 10³ N = 1.9 × 10⁴ N

  • Step 3. Calculate the power exerted by the bodybuilder.

The bodybuilder does a work of 1.9 × 10⁴ N in a 45-s span.

P = 1.9 × 10⁴ N/45 s = 421 W

A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)

Learn more about power here: brainly.com/question/911620

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4 0
1 year ago
A bedroom bureau with a mass of 45 kg, including drawers and clothing, rests on the floor. (a) If the coefficient of static fric
sergij07 [2.7K]

Answer: the minimal force that you need to apply to move the bureau is F = 198.45N

Explanation:

If you want to move an object, you need to apply a force that is bigger than the force of the statical friction.

The force of statical friction can be written as.

Ff = k*N

where k is the coefficient of static friction, in this case, k = 0.45, and N is the normal force between the object and the surface.

In this case, the normal force is the weight of the bedroom bureau, this is:

N = m*g = 45kg*9.8m/s^2 = 441N

Then the force is:

Fr = 0.45*441N = 198.45N

This means that the minimal force that you need to apply to move the bureau is F = 198.45N

and after this point, the force of friction will work wit the kinetic coefficient of friction, that usually is smaller than the statical one.

4 0
3 years ago
ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements.
natali 33 [55]

Answer:

Well I'm going to go with A.

Explanation:

As per the question the mass of the boy is 40 kg.

The boy sits on a chair.

We are asked to calculate the force exerted by the boy on the chair at sea level.

The force exerted by boy on the chair while sitting on it is nothing else except the force of gravity of earth i.e the weight of the body .The direction of that force is vertically downward.

At sea level the acceleration due to gravity g = 9.8 m/s^2

Therefore, the weight of the boy  [m is the mass of the body]

we have m = 40 kg.

                             Therefore, w = 40 kg ×9.8 m/s^2

                                             =392 N kg m/s^2

                                              = 392 N

392 is not an option but I'm guessing you can round down 2 .to option A. 390...?

8 0
3 years ago
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