Question

A mass of mercury occupies 0.750 L. What volume would an equal mass of ethanol occupy? The density of mercury is 13.546 g/mL, and the density of ethanol is 0.789 g/mL.

Answer 1

Answer:

Ve=12876.43mL  : Ethanol volume

Explanation:

We apply the formula to calculate the density:

ρ=$\frac{m}{V}$ Formula (1)

Where:

ρ:Density in g/mL

m: mass in g (grams)

V= Volume in ml (milliliters)

We know the following data:

1L= 1000mL

Vm=Volume of mercury:VHg=0.750 L*1000mL/L=750mL

ρ-m=Density of mercury =13.546 g/mL

ρ-e: density of ethanol is 0.789 g/mL

$m_{m} =m_{e}$

Development of the problem:

In formula 1 We replace the known data for the  mercury :

ρ-m=$\frac{m_{m} }{V_{m} }$

$13.546 \frac{g}{mL} =\frac{m_{m} }{750mL}$

$m_{m}=13.546 \frac{g}{mL}*750mL$

$m_{m} =10159.5 g$

We know that $m_{e} =m_{m} =10159.5 g$, then, We replace the known data for the  ethanol In formula 1:

ρ-e=$\frac{m_{e} }{V_{e} }$

$0.789 \frac{g}{mL} =\frac{10159.5g}{V_{e} }$

$Ve=\frac{10159.5 g}{0.789 \frac{g}{mL}}$

$Ve=12876.43mL$