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Katena32 [7]
4 years ago
9

To a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s. from the woman's frame of reference, what

is the man's velocity?
Physics
2 answers:
neonofarm [45]4 years ago
5 0
T o a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s. from the woman's frame of reference, what is the man's velocity? it is 4m/s east
barxatty [35]4 years ago
5 0

Answer: 4 m/s (towards East)

Explanation:

The velocity of man jogging with respect to a stationary observer, Vm = +2.5 m/s (Eastwards)

The velocity of woman jogging with respect to a stationary observer, Vw = -1.5 m/s (Westwards)

In woman's frame of reference, the man would be jogging relatively faster in the opposite direction as she is in motion herself.

From the woman's frame of reference, the man's velocity:

Vmw = Vm-Vw = +2.5 m/s - (-1.5 m/s) = +4.0 m/s (Eastwards)

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It is given that,

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