Answer:
50.2 meters
Explanation:
When an object falls, it goes a distance d in time t according to the formula:
d is the distance in meter, g is the acceleration due to gravity with the value of 9.8
, t is the time in seconds
Therefore, 
d= 50.176 ≈ 50.2m
Answer:
K.E = 1.28 × 10^-17 KeV
Explanation:
Given that a particle accelerator at CERN can accelerate an electron through a potentialdifference of 80 kilovolts.
To Calculate the kinetic energy (in keV) of the electron, let us first find the electron charge which is 1.60 × 10^-19C
The kinetic energy = work done
K.E = e × kV
Substitute e and the voltage into the formula
K.E = 1.60 × 10^-19 × 80
K.E = 1.28 × 10^-17 KeV
Therefore, the kinetic energy is approximately equal to 1.28 × 10^-17 KeV
The equatorial radius of the earth is
r = 6378 km = 6378 x 10³ m
The earth makes 1 revolution in 24 hours.
The angular velocity is
ω = (2π rad)/(24*3600 s) = 7.2722 x 10⁻⁵ rad/s
The tangential velocity (linear velocity) at a point on the equator is
v = rω
= (6378 x 10³ m)*(7.2722 x 10⁻⁵ rad/s)
= 463.8 m/s
Answer: 463.8 m/s
Answer:
0.0003 m = 0.3 mm
Explanation:
For constructive interference in the Young's experiment.
The position of the mth fringe from the central fringe is given by
y = L(mλ/d)
λ = wavelength = 720 nm = 720 × 10⁻⁹ m
L = distance between slits and screen respectively = 1.0 m
d = separation of slits = 0.68 mm = 0.68 × 10⁻³ m
m = 2
y = 1(2 × 720 × 10⁻⁹/(0.68 × 10⁻³) = 0.00212 m = 2.12 mm
For the 620 nm light,
y = 1(2 × 620 × 10⁻⁹/(0.68 × 10⁻³) = 0.00182 m = 1.82 mm
Distance apart = 2.12 - 1.82 = 0.3 mm = 0.0003 m
First we'll calculate the energy it posesses
G.P.E = mgh = 0.2 * 10 * 100 = 200 J
Now we'll calculate the temperature rise
Q = m * c * (t2 - t1)
Q/(m * c) = t2-t1
t2 = Q/(m * c) + t1 = 200/(0.2 * 400) + 0 = <span>2.5 C</span>
