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Katena32 [7]
4 years ago
9

To a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s. from the woman's frame of reference, what

is the man's velocity?
Physics
2 answers:
neonofarm [45]4 years ago
5 0
T o a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s. from the woman's frame of reference, what is the man's velocity? it is 4m/s east
barxatty [35]4 years ago
5 0

Answer: 4 m/s (towards East)

Explanation:

The velocity of man jogging with respect to a stationary observer, Vm = +2.5 m/s (Eastwards)

The velocity of woman jogging with respect to a stationary observer, Vw = -1.5 m/s (Westwards)

In woman's frame of reference, the man would be jogging relatively faster in the opposite direction as she is in motion herself.

From the woman's frame of reference, the man's velocity:

Vmw = Vm-Vw = +2.5 m/s - (-1.5 m/s) = +4.0 m/s (Eastwards)

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horrorfan [7]

Explanation:

Mass of the ball, m = 0.058 kg

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Time, t = 2.1 s

(a) Let F is the average force exerted on the wall. It is given by :

F=\dfrac{m(v-u)}{t}

F=\dfrac{0.058\times (11-(-11))}{2.1}

F = 0.607 N

(b) Area of wall, A=3\ m^2

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Hence, this is the required solution.

8 0
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Physical form in which a substance can exist 
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A 1200 kg car accelerates from 13 m/s to 17 m/s. find the change in momentum of the car.
mixas84 [53]
P=4800kgm/s
As
p=mΔv
where p is momentum, m is mass and v is velocity
Given values is
m =1200kg
Δv= 17m/s-13m/s=4m/s
Now
p=mΔv
p=(1200kg)*(4m/s)
p=4800kgm/s


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2 years ago
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