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Katena32 [7]
3 years ago
9

To a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s. from the woman's frame of reference, what

is the man's velocity?
Physics
2 answers:
neonofarm [45]3 years ago
5 0
T o a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s. from the woman's frame of reference, what is the man's velocity? it is 4m/s east
barxatty [35]3 years ago
5 0

Answer: 4 m/s (towards East)

Explanation:

The velocity of man jogging with respect to a stationary observer, Vm = +2.5 m/s (Eastwards)

The velocity of woman jogging with respect to a stationary observer, Vw = -1.5 m/s (Westwards)

In woman's frame of reference, the man would be jogging relatively faster in the opposite direction as she is in motion herself.

From the woman's frame of reference, the man's velocity:

Vmw = Vm-Vw = +2.5 m/s - (-1.5 m/s) = +4.0 m/s (Eastwards)

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What is air pressure?
dolphi86 [110]

Answer:

A. Earth's gravity pulling down on air molecules

Explanation:

Air pressure refers to the weight of the air per unit surface area. It is the amount of gravitational force which is pulling down the molecules of air.

The common unit of air pressure is: Pascal, atm

1 atm = 101325 Pa

As the column of the air above increases, the air pressure increase. This is because with the increase in amount of air, the weight increase of the air increases. This is the reason a diver feels immense pressure in the sea and cooking takes a lot of time on hilly areas because of low air pressure.

5 0
3 years ago
A guitarist finds that the pitch of one of her strings is slightly flat—the frequency is a bit too low. Should she increase or d
Yuri [45]

Answer:

The guitarist should increase the tension of the string.

Explanation:

The frequency of a vibrating string is determined by fn=(n/(2L))√T/μ. So if the tension in the string increased, the rate at which it vibrates (the frequency) will also increase.

Therefore it is advisable that she increase the tension of the string.

I hope it helps, please give brainliest if it does

6 0
3 years ago
4. While broadcasting a football game, the announcer exclaimed, "I can't believe it. Carl James just scored a touchdown. That's
Zielflug [23.3K]
D. Carl doesnt score touchdowns very often.
7 0
3 years ago
Read 2 more answers
Solve for the unknown in each of these circuits
Tamiku [17]

<u> Ohms law: </u> This law relates voltage difference between two points. Mathematically, the law states that V=IR;

                Where

                          V = voltage difference ; in volts

                          I = Current ; in Amperes

                          R = Resistance ; in ohms

<u>1. Answer : </u> given that R = 10 ; V= 12 V ;  I = ?

From ohms law,    I = V/R

                                = 12/10

                                = 1.2 Amp.

<u>2. Answer:</u>  given that R = 10 ; V= ? ;  I = 5

From ohms law,    V = IR

                                 = 10×5 = 50 V

<u>3 . Answer:</u>  given that R = ? ; V= 120 ;  I = 5

From ohms law,    R =  V/I

                                 = 120/5

                                 = 24 Ω

<u>4 . Answer:</u>  given that R = ? ; V= 10 ;  I = 20

From ohms law,    R =  V/I

                                 = 10/20

                                 = 0.5 Ω

<u>5 . Answer:</u>  given that R = 480 ; V= 24 ;  I = ?

From ohms law,  I =  V/R

                              = 24/480

                              = 0.05 A

<u>6. Answer:</u>  given that R = 150 ; V= ? ;  I = 1

From ohms law,  V = IR

                               = 1 × 150

                               = 150 V


6 0
3 years ago
The a992 steel rod bc has a diameter of 50 mm and is used as a strut to support the beam. determine the maximum intensity w of t
EastWind [94]

Answer:

w = 11.211 KN/m

Explanation:

Given:

diameter, d = 50 mm

F.S = 2

L = 3

Due to symmetry, we have:

Ay = By = \frac{w * 6}{2} = 3w

P_c_r = 3w * F.S = 3w * 2.0 = 6w

I = \frac{\pi}{64} (0.05)^4 = 3.067*10^-^7

To find the maximum intensity, w, let's take the Pcr formula, we have:

P_c_r = \frac{\pi^2 E I}{(KL)^2}

Let's take k = 1

E = 200*10^9

Substituting figures, we have:

6w = \frac{\pi^2 * 200*10^9 * 3.067*10^-^7}{(1 * 3)^2}

Solving for w, we have:

w = \frac{67266.84}{6}

w = 11211.14 N/m = 11.211 KN/m

Since Area, A= pi * (0.05)²

\sigma _c_r = \frac{w}{A}

\sigma _c_r = \frac{11.211}{\pi (0.05)^2} = 1.4 MPA < \sigma y. This means it is safe

The maximum intensity w = 11.211KN/m

3 0
3 years ago
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