4 years ago

Y=a log(ab)/(c+d) find dimension of a b c

Physics

1 answer:

Mandarinka [93]4 years ago

8 0

Explanation:

aiwb qidb she is to the dimension of a

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A block moves up a 30 degree incline under the action of three applied forces. F1 is horizontal and of magnitude 40 N. F2 is nor

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Answer

given,

F₁ is horizontal = 40 N

F₂ is normal = 20 N

F₃ is parallel = 30 N

work done by

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W₃ = F₃ x d

W₃ = 30 x 0.8

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W₁ = F₁ x d

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W₁ = 40 cos 30⁰ x 0.8

W₁ = 27.21 J

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Find the force on a 5 pС charge in a place where the electric field is 400 N/C.

mote1985 [20]

Answer:

Electric force, $F=2\times 10^{-9}\ N$

Explanation:

It is given that,

Charge on the particle, $q=5\ pC=5\times 10^{-12}\ C$

Electric field, $E=400\ N/C$

Let F is the electric force acting on the charged particle. The electric force per unit electric charge is called electric field. Mathematically, it is given by :

$F=qE$

$F=5\times 10^{-12}\ C\times 400\ N/C$

$F=2\times 10^{-9}\ N$

So, the force acting on the charged particle is $2\times 10^{-9}\ N$ . Hence, this is the required solution.

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3 years ago

Y=a log(ab)/(c+d) find dimension of a b c​

Y=a log(ab)/(c+d) find dimension of a b c