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Elena-2011 [213]
3 years ago
8

PLEASE HELP!!!!

Chemistry
1 answer:
castortr0y [4]3 years ago
6 0

Answer:

B

IS THE CORRECT ANSWER

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*click photo* <br><br> Tysm if you answer!
STALIN [3.7K]

Answer: False

Explanation:

AC change directions and DC only flow in one direction

4 0
4 years ago
Read 2 more answers
What is the mass, in grams, of a sample of 1.20 × 1022 atoms of mercury (Hg)? Show your work or explain the steps that you used
o-na [289]
Atomic mass Hg = 200.59 u.m.a

200.59 g --------------- 6.02x10²³ atoms
( mass Hg ) ----------- 1.20 x10²² atoms

mass Hg = ( 1.20x10²² ) x 200.59 / 6.02x10²³

mass Hg = 2.407x10²⁴ / 6.02x10²³

= 3.998 g of Hg

hope this helps!
5 0
4 years ago
Read 2 more answers
jelani and Mikah are watching an approaching storm from their living room window. All of a sudden they see a bright flash of lig
Shtirlitz [24]

Answer: Heat causes surrounding air to rapidly expand and vibrate, which creates the pealing thunder we hear a short time after seeing a lightning flash.

4 0
3 years ago
A fusion reaction always creates which of the following?
ICE Princess25 [194]

A fusion reaction can be regarded as the type of reaction that occurs where two lighter elements come together in a type of reaction giving rise to a heavier/more massive element.

A fusion reaction always creates a more massive atomic nucleus (option c).

When the two lighter nuclei comes together in a reaction, a more heavier/massive nucleus is formed but its mass will still be less than the combined mass of the two reactant nuclei.

This also indicates that the left over mass may have been released as energy.

Learn more: brainly.com/question/18175586

6 0
3 years ago
Calculate the theoretical yield for the bromination of both stilbenes
podryga [215]

Answer:

cinnamic acid - 150 mg

cis-stilbene - 100 μL

trans- stilbene - 100 mg

pyridinium tribromide - 200-385 mg

For this data:

moles of cinnamic acid = 0.150 g/148.16 g/mol = 0.001 mols

Theoretical mass of dibromoproduct formed = 0.001 mol x 307.97 g/mol = 0.312 g

cis-stilbene (100 ul = 0.1 ml)

moles of cis-stilbene = 0.1 ml x 1.01 g/mol/180.25 g/mol = 0.00056 mols

Theoretical mass of dibromoproduct formed = 0.00056 mol x 340.05 g/mol = 0.19 g

trans-stilbene

moles of tran-stilbene = 0.1 g/180.25 g/mol = 0.00055 mols

Theoretical mass of dibromoproduct formed = 0.00055 mol x 340.05 g/mol = 0.19 g

Explanation:

4 0
2 years ago
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