Answer:
v = √ 2 G M/ 
Explanation:
To find the escape velocity we can use the concept of mechanical energy, where the initial point is the surface of the earth and the end point is at the maximum distance from the projectile to the Earth.
Initial
Em₀ = K + U₀
Final
= 
The kinetic energy is k = ½ m v²
The gravitational potential energy is U = - G m M / r
r is the distance measured from the center of the Earth
How energy is conserved
Em₀ =
½ mv² - GmM / = -GmM / r
v² = 2 G M (1 / – 1 / r)
v = √ 2GM (1 / – 1 / r)
The escape velocity is that necessary to take the rocket to an infinite distance (r = ∞), whereby 1 /∞ = 0
v = √ 2GM /
Base SI unit is the unit that used for simple quantity like time=second and length= meter. They only have one unit.
Derived unit is more complex because you multiply or divide at least two base SI, making it have more than 1 unit. The example could be velocity which was time/length = m/s
Answer:
Explanation:
As we know that the formula of range is given as
now we know that
maximum value of the range of the projectile is given as
now we need to find such angles for which the range is half the maximum value
so we will have
Answer:
A fired bullet
Explanation:
A fired bullet is faster than the speed of sound
Answer:
Magnitude of electric field is 1.06 x 
V/m along negative X-direction
Explanation:
Given: initial velocity of proton = u = 3.5 x 
m/s
final velocity of proton = v = 0 m/s
initial point 
= 0.2 m and final point is 
= 0.8 m
According to conservation of energy:
change in in kinetic energy = change in potential energy of proton
⇒
where q and m is the charge and mass of proton E is the electric field , and is the initial and final position of proton
on substituting the respected values we get,
1.023 x 
= 9.6 x 
x E
⇒ E = 1.06 x V/m
external force is opposite to the motion as velocity of proton decreases with distance.
Therefore, magnitude of electric field is 1.06 x V/m along negative X-direction
