Answer:
a)
, b) 
Explanation:
The problem is asking the rocket velocity and acceleration at t = 6 s.
a) The general equation of the rocket is:



b) The acceleration experimented by the rocket is:



The energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.
<h3>Conservation of energy</h3>
The amount of energy lost due to air resistance while she was bouncing is determined from the principle of conservation of energy.
ΔE = P.E - Ux
ΔE = mgh - ¹/₂kx²
ΔE = (50)(9.8)(16) - ¹/₂(35)(16)²
ΔE = 3,360 J
Thus, the energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.
Learn more about energy here: brainly.com/question/13881533
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Answer:
V = 0.074 m/s
Explanation:
given,
mass of the receiver, M = 96 Kg
mass of the ball, m = 0.42 Kg
initial speed of the ball, v = 17 m/s
initial speed of the receiver = 0 m/s
final speed.V = ?
using conservation of momentum
M u + m v = (M + m) V
0 + 0.42 x 17 = (96+0.42) V
96.42 V = 7.14
V = 0.074 m/s
hence, Speed after catching the ball is equal to 0.074 m/s