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Ludmilka [50]
3 years ago
13

What do u do when your parent is giving u a hard time​

Physics
2 answers:
posledela3 years ago
4 0
Take 10 deep breaths
elixir [45]3 years ago
3 0

Answer:

calm down and be nice

Explanation:

You might be interested in
A small, 150 g cart is moving at 1.60 m/s on a frictionless track when it collides with a larger, 5.00 kg cart at rest. After th
NemiM [27]

Answer:

Mass of larger cart will be 0.0213 m /sec

Explanation:

We have given mass of small cart m_1=150gram=0.150kg

Initial velocity of small cart v_{1i}=1.6m/sec

Mass of larger block m_2=5kg

Initial velocity of larger cart v_{2i}=0m/sec

After the collision velocity of smaller cart v_{1f}=-0.890m/sec

Now according conservation of momentum

m_1v_{1i}+m_2v_{2i}=m_1v{1f}+m_2v_{2f}

0.150\times 1.6+5\times 0=0.150\times -0.890+5\times v_{2f}

5\times v_{2f}=0.1065

v_{2f}=0.0213m/sec

5 0
3 years ago
Which of the following objects is NOT accelerating?
MatroZZZ [7]

Answer:

A Bicycle

Explanation:

A Space shuttle accelerating because the Earth pulls on it through the gravitational force.

A Truck is accelerating because acceleration is necessary for an object to change direction.

A car is accelerating because it is speeding up unexpectedly?????

4 0
3 years ago
If you double the force an object what will hapen to the accelration
melamori03 [73]

Explanation:

the acceleration will double because force is directly proportional to the acceleration

3 0
3 years ago
Read 2 more answers
The curved path traveled by a thrown baseball is known as what?
musickatia [10]

Projectile motion.


hope this helps!

-Payshence

6 0
4 years ago
A doorframe is twice as tall as it is wide. There is a positive charge on the top left corner and an equal but negative charge i
Andrei [34K]

Answer:

α = 141.5°  (counterclockwise)

Explanation:

If

q₁ = +q

q₂ = -q

q₃ < 0

b = 2*a

We apply Coulomb's Law as follows

F₁₃ = K*q₁*q₃ / d₁₃² = + K*q*q₃ / (2*a)² = + K*q*q₃ / (4*a²)

F₂₃ = K*q₂*q₃ / d₂₃² = - K*q*q₃ / (5*a²)

(d₂₃² = a² + (2a)² = 5*a²)

Then

∅ = tan⁻¹(2a/a) = tan⁻¹(2) = 63.435°

we apply

F₃x = - F₂₃*Cos ∅ = - (K*q*q₃ / (5*a²))* Cos 63.435°

⇒  F₃x = - 0.0894*K*q*q₃ / a²

F₃y = - F₂₃*Sin ∅ + F₁₃

⇒  F₃y = - (K*q*q₃ / (5*a²))* Sin 63.435° + (K*q*q₃ / (4*a²))

⇒  F₃y = 0.0711*K*q*q₃ / a²

Now, we use the formula

α = tan⁻¹(F₃y / F₃x)

⇒  α = tan⁻¹((0.0711*K*q*q₃ / a²) / (- 0.0894*K*q*q₃ / a²)) = - 38.5°

The real angle is

α = 180° - 38.5° = 141.5°  (counterclockwise)

4 0
4 years ago
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