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3 years ago

Write the balanced equation for the oxidation of iron to iron (III) oxide. Will mark brainlest answer

Chemistry

1 answer:

Butoxors [25]3 years ago

5 0

Start with the unbalanced chemical equation

Fe(s)+O2(g)→Fe2O3(s)

The idea behind balancing chemical equations is that the number of atoms an element has on the reactants' side must be equal to the number of atoms it has on the products' side.

These atoms will become a part of different compounds once the reaction is completed, but they must always be in equal numbers on both sides.

So, look at iron first. One atom reacts, but two are produced - notice the 2 subscript iron has in Fe2O3. This means you must double the number of atoms on the reactants' side to reach an equality.2

Fe(s)+O2(g)→Fe2O3(s)

Now look at oxygen. Two atoms react, but three are produced. The trick here is to find a common multiple that will make the number of atoms equal on both sides.

The easiest way to do this is to multiply the atoms that react by 3, which will give you 6 oxygen atoms that react, and the atoms that are produced by 2 - this will get you 6 oxygen atoms produced.

2Fe(s)+3O2(g)→2Fe2O3(s)

However, notice that the iron atoms are unbalanced again. You have 2 that react, but 4 that are produced → multiply the atoms that react by 2 again, which will give you

4Fe(s)+3O2(g)→2Fe2O3(s

You might be interested in

A chemist determined by measurements that 0.050 moles of tin participated in a chemical reaction. Calculate the mass of tin that

stepladder [879]

Answer:

Explanation:

MM of I2 = 2 (127 g) = 254 g/mol

0.065 mol I2 x 254g I₂/ 1 mol I₂ = 16.5 g I2

8 0

3 years ago

Read 2 more answers

A gas has a pressure of 853.0 millibars at a temperature of 29.0 °C. If the volume is unchanged but the temperature is increased

Nitella [24]

The new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars. Details about pressure can be found below.

<h3>How to calculate pressure?</h3>

The pressure of a given gas can be calculated using the following formula:

P1/T1 = P2/T2

Where;

P1 = initial pressure = 853.0 millibars
P2 = final pressure = ?
T1 = initial temperature = 29°C + 273 = 302K
T2 = final temperature = 85°C + 273 = 358K

853/302 = P2/358

358 × 853 = 302P2

305374 = 302P2

P2 = 305374 ÷ 302

P2 = 1011.17 millibars

Therefore, the new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars.

Learn more about pressure at: brainly.com/question/15175692

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8 0

2 years ago

To understand the relation between the strength of an acid or a base and its pKa and pKb values. The degree to which a weak acid

elena-14-01-66 [18.8K]

Answer:

pKa = 3.675

Explanation:

pKa = - Log Ka

∴ C X-281 = 0.079 M

∴ pH = 2.40

let X-281 a weak acid ( HA ):

∴ HA ↔ H+ + A-

⇒ Ka = [H+] * [A-] / [HA]

mass balance:

⇒ C HA = 0.079 M = [HA] + [A-]

⇒ [HA] = 0.079 - [A-]

charge balance:

⇒ [H+] = [A-] + [OH-]... [OH-] is negligible; it comes from to water

⇒ [H+] = [A-]

∴ pH = - log [H+] = 2.40

⇒ [H+] = 3.981 E-3 M

replacing in Ka:

⇒ Ka = [H+]² / ( 0.079 - [H+] )

⇒ Ka = ( 3.981 E-3 )² / ( 0.079 - 3.981 E-3 )

⇒ Ka = 2.113 E-4

⇒ pKa = - Log ( 2.113 E-4 )

⇒ pKa = 3.675

8 0

3 years ago

What element has 3 protons and neutrons

gregori [183]

Answer:

i believe lithium dont clown me if im wrong

Explanation:

5 0

2 years ago

Read 2 more answers

1. Using the Slater rule, determine the effective nuclear charge of platinum.

AleksandrR [38]

Answer:

Z* = 3.55

Explanation:

Slater rule says that:

Z*= Z - S

Z* be the nuclear effective charge

Z is the nuclear charge

S is the shielding constant

First we write the electronic configuration of platinum: $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 4d^{10} 5s^{2} 5p^{6} 4f^{14} 5d^{9} 6s^{1}$

The first Slater rule says that we need to group:

$(1s^{2}) (2s, 2p)^{8} (3s, 3p)^{8} (3d^{10}) (4s, 4p)^{8} (4d^{10}) (5s, 5p)^{8} (4f^{14}) (5d^{9}) (6s^{1})$

The second rule says that the electrons to the right are not shielding, but we are going to solve the exercise for the last level (6s), so we don't have electrons to the right.

For the third rule we have two considerations, if is ns or np and if is nd or nf:

For our case, we have an electro that is in ns, so the rule says that

-electrons within same group shield 0.35, except the 1s which shield 0.30

-electrons within the n-1 group shield 0.85

-electrons within the n-2 or lower groups shield 1.00

Now we can proceed with the calculation:

The first consideration in the third rule does not apply as we only have one electron on this level.

The second consideration will be as follow for the level 5, where we have 17 electrons.

Finally the third consideration will be for levels 1, 2, 3 and 4, where we have 14 for 4f, 10 for 4d, 8 for 4s and 4p, 10 for 3d, 8 for 3s and 3p, 8 for 2s and 2p and finally 2 for 1s, which gives 60 electrons.

So the result for S=(60*1.00 + 17*0.85) = 74.45

And the equation is: Z* = 78 - 74.45

So Z* = 3.55

3 0

3 years ago