Answer:
Atoms consist of a nucleus made of protons and neutrons orbited by electrons.
Isotopes are atoms that have same number of protons but they differ in the number of neutrons and in atomic mass.
I would think the answer would be C. Based off of what I've learned and heard. Sorry if it's not the correct answer though.
First; use the relationship of molarity and moles/liter to find the moles of the solution.
so 0.600M ×0.030L = 0.018 moles
Then use the mole to mole ratio of lithium to lithium carbonate
0.18 × (2 Li ÷1 Li2CO3) = 0.036
and then multiply by Avogadro's number to find the ions of lithium
0.036 moles × (6.022×10^{23} ) = 2.167 ×10∧22 ions Li
Answer:
pH = 2.03
Explanation:
The pH can be calculated using the following equation:
![pH = -log [H_{3}O^{+}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-log%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20)
(1)
The concentration of H₃O⁺ is calculated using the dissociation constant of the next reaction:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺
1.00 M
![K_{a} = \frac{[CH_{3}COO^{-}][H_{3}O^{+}]}{[CH_{3}COOH]}](https://tex.z-dn.net/?f=%20K_%7Ba%7D%20%3D%20%5Cfrac%7B%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BCH_%7B3%7DCOOH%5D%7D%20)
Solving the above equation for H₃O⁺, we have:
![[H_{3}O^{+}] = \frac{Ka*[CH_{3}COOH]}{[CH_{3}COO^{-}]}](https://tex.z-dn.net/?f=%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7BKa%2A%5BCH_%7B3%7DCOOH%5D%7D%7B%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%7D%20)
(2)
The dissociation constant is equal to:
Now, by solving the equation of the solubility product for Herbigon, we can find [CH₃COO⁻]:
CH₃COOX ⇄ CH₃COO⁻ + X⁺
5.00x10⁻³ M
![K_{sp} = [CH_{3}COO^{-}][X^{+}]](https://tex.z-dn.net/?f=%20K_%7Bsp%7D%20%3D%20%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%5BX%5E%7B%2B%7D%5D%20)
![[CH_{3}COO^{-}] = \frac{K_{sp}}{[X^{+}]} = \frac{9.40 \cdot 10^{-6}}{5.00 \cdot 10^{-3}} = 1.88 \cdot 10^{-3} M](https://tex.z-dn.net/?f=%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%20%3D%20%5Cfrac%7BK_%7Bsp%7D%7D%7B%5BX%5E%7B%2B%7D%5D%7D%20%3D%20%5Cfrac%7B9.40%20%5Ccdot%2010%5E%7B-6%7D%7D%7B5.00%20%5Ccdot%2010%5E%7B-3%7D%7D%20%3D%201.88%20%5Ccdot%2010%5E%7B-3%7D%20M)
By entering the values of [CH₃COO⁻] and Ka, into equation (2) we can calculate [H₃O⁺]:
![[H_{3}O^{+}] = \frac{1.74 \cdot 10^{-5}*[1.00]}{[1.88 \cdot 10^{-3}]} = 9.26 \cdot 10^{-3} M](https://tex.z-dn.net/?f=%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B1.74%20%5Ccdot%2010%5E%7B-5%7D%2A%5B1.00%5D%7D%7B%5B1.88%20%5Ccdot%2010%5E%7B-3%7D%5D%7D%20%3D%209.26%20%5Ccdot%2010%5E%7B-3%7D%20M)
Hence, the pH is:
![pH = -log [H_{3}O^{+}] = -log [9.26 \cdot 10^{-3}] = 2.03](https://tex.z-dn.net/?f=%20pH%20%3D%20-log%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%20-log%20%5B9.26%20%5Ccdot%2010%5E%7B-3%7D%5D%20%3D%202.03%20)
Therefore, the pH must be 2.03 to yield a solution in which the concentration of X⁺ is 5.00x10⁻³M.
I hope it helps you!
Answer: remains constant.
Justification:
1) The phase changes are:
i) Boiling: pass from liquid to gas (absorbs heat energy)
ii) Condensation: pass from gas to liquid (release heat energy)
iii) Melting: pass from solid to liquid (absorb heat energy)
iv) Freezing: pass from liquid to solid (release heat energy)
v) Sublimation: pass from solid to gas (absorbs heat energy)
vii) Deposition: pass from gas to solid (release heat energy)
2) When a phase change occurs, whichever it is, the heat energy related with the process, either absortion or release, is used, to overcome the intermolecular forces (in the case of heat energy absortion) or to create stronger intermolecular forces (in the case of heat energy release).
Because of that, the heat energy exchange does not change the temperature of the substance.
