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Schach [20]
3 years ago
7

What is the volume occupied by 4.20 miles of oxygen gas (O2) at STP

Chemistry
1 answer:
Drupady [299]3 years ago
8 0

Answer: 94.13 L

Explanation: In STP in an ideal gas there is a standard value for both temperature and pressure. At STP,pressure is equal to 1atm and the temperature at 0°C is equal to 273.15K. This problem is an ideal gas so we use PV=nRT where R is a constant R= 0.08205 L.atm/mol.K.

To find volume, derive the equation, it becomes V=nRT/P. Substitute the values. V= 4.20 mol( 0.08205L.atm/mol.K)(273.15K) / 1 atm = 94.13 L. The mole units, atm and K will be cancelled out and L will be the remaining unit which is for volume.

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How many cm are equal to 1.45 m
Dima020 [189]

There are 145 centimeters in 1.45 meters.

8 0
3 years ago
Calculate the amount in grams of Na2CO3 needed in a reaction with HCl to produce 120g NaCl?
klemol [59]
The balanced chemical reaction is written as :

Na2CO3<span> + 2HCl === 2NaCl + H2O + CO2
</span>
We are given the amount of NaCl to be produced from the reaction. This will be the starting point for the calculations. We do as follows:

120 g NaCl ( 1 mol / 58.44 g) ( 1 mol Na2CO3 / 2 mol NaCl)( 105.99 g / 1 mol ) = 1108.82 g Na2CO3 needed
8 0
3 years ago
Americans eat too much salt (NaCl). A healthy adult should eat no more than 6 g of salt in one day. Use this information to answ
Rufina [12.5K]

Answer:

a. 58.5 g/mol

b. 0.1 mol

Explanation:

a.

The molar mass of Na is 23.0 g/mol. The molar mass of Cl is 35.5 g/mol. The molar mass of NaCl is:

M(Na) + M(Cl) = 23.0 g/mol + 35.5 g/mol = 58.5 g/mol

b. A healthy adult should eat no more than 6 g of salt in one day. The moles corresponding to 6 g of NaCl are:

6 g × (1 mol/58.5 g) = 0.1 mol

7 0
3 years ago
Calculate the moles of octane needed to provide 0.065 mol or water.
gavmur [86]

Answer:

0.007 moles of octane

Explanation:

Balanced Equation: 2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

0.065 mol H₂O * 2 mol C₈H₁₈/18 mol H₂O = 0.00722... = 0.007 mol C₈H₁₈

8 0
3 years ago
The decay constant for 14C is .00012 In 1947, the famous cave paintings in Lascaux, France were discovered and testing revealed
Andru [333]

The question is incomplete, here is the complete question:

The decay constant for 14-C is 0.00012yr^{-1} In 1947, the famous cave paintings in Lascaux, France were discovered and testing revealed that charcoal in the cave contained 20% of the 14-C found in living trees. Write a formula for the age of the charcoal (hence of the associated paintings). Show your work to find this formula.

<u>Answer:</u> The formula for the age of the charcoal is t=\frac{2.303}{1.2\times 10^{-4}yr^{-1}}\log \frac{100}{20}

<u>Explanation:</u>

Carbon-14 isotope is a radioisotope and its decay process follows first order kinetics.

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant  = 0.00012yr^{-1}=1.2\times 10^{-4}yr^{-1}

t = time taken for decay process = ? yr

[A_o] = initial amount of the sample = 100 grams

[A] = amount left after decay process = (100 - 20) = 80 grams

Putting values in above equation, we get:

1.2\times 10^{-4}=\frac{2.303}{t}\log\frac{100}{20}\\\\t=\frac{2.303}{1.2\times 10^{-4}yr^{-1}}\log \frac{100}{20}

Hence, the formula for the age of the charcoal is t=\frac{2.303}{1.2\times 10^{-4}yr^{-1}}\log \frac{100}{20}

5 0
4 years ago
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