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Vinvika [58]
2 years ago
11

A remnant or trace of an organism from the past is called a

Chemistry
2 answers:
ollegr [7]2 years ago
7 0

Answer:Fossil

Explanation:A remnant or trace of an organism of a past geologic age, such as a skeleton or leaf imprint, embedded, and preserved in the Earth's crust, usually in stratified rock.

Makovka662 [10]2 years ago
6 0

Answer:

a fossil

Explanation:

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Describe the relationship of pressure and temperature in the center of the Earth.
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The answer should be c because the relationship of pressure and plus the temperature decrease in the center.
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2 years ago
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Chemical formula name for V2(SO2)3 (aq) explain why​
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This is the chemical doula for salt which is a polyatomic anion very prevalent in out daily lives e.g.

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3 0
3 years ago
Anouk does 150 J of work using a hammer to pull a nail out of a piece of wood, and the hammer does 105 J of work on the nail. Wh
astraxan [27]
The efficiency of any machine is given by:

efficiency = output obtained / input given

Substituting the values,
Efficiency = 105 / 150
Efficiency = 0.7

Converting this to a percentage, the efficiency of the hammer is 70%.
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3 years ago
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What would be the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg?
Anna [14]

Answer: The temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 2300 mm Hg = 3.02 atm  (760mmHg=1atm)

V = Volume of gas = 15 L

n = number of moles = 0.6

R = gas constant =0.0821Latm/Kmol

T =temperature = ?

T=\frac{PV}{nR}

T=\frac{3.02atm\times 15L}{0.0821Latm/K mol\times 0.6mol}=920K

Thus the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K

8 0
3 years ago
A sample of Neon is in a sealed container held under isothermic conditions. The initial pressure and volume are 2.7 atm and 4.5
Marina CMI [18]

Answer:

The final volume in mL is 7.14 mL or 7.1 mL.

Explanation:

1.Use Boyle's Law(P_{1} V_{1}= P_{2} V_{2}). Re-arrange to solve for V_{2}<em> for the final volume.</em>

<em />

<em>2. Plug in values. </em>V_{2} =\frac{(2.7 atm)(4.5 mL)}{(1.7 atm)}  = 7.14 mL

3 0
2 years ago
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