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aleksandr82 [10.1K]
2 years ago
10

Suggest a name for a compound containing potassium, carbon and oxygen.

Chemistry
1 answer:
spin [16.1K]2 years ago
4 0

Answer:

Oxidation of potassium amalgam with carbon dioxide results in the formation of potassium oxalate. Potassium is not reactive with benzene, although heavier alkali metals such as cesium react to give organometallic products.

Please Mark Brainliest If This Helped!

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The mass number minus the atomic number
Furkat [3]
Equals the # of neutrons
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3 years ago
What is the limiting reactant if 12 moles of p4 react with 15 moles of o2?.
brilliants [131]

Answer:

see explanation

Explanation:

To determine limiting reactant divide mole quantities of reactants by the respective coefficient in the balanced equation. The smaller value is the limiting reactant.

    P₄      +     5O₂       => 2P₂O₅

12/1 = 12      15/5 = 3

O₂ is the limiting reactant. P₄ will be in excess when rxn stops.

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2 years ago
Given the following data, determine the order of reaction with respect to H2.
alex41 [277]

Answer:

First-order with respect to hydrogen.

Explanation:

Hello!

In this case, considering that the rate law of this reaction can be expressed via:

r=k*p_{H_2}^m*p_{ICl}^n

If we want to know m, the order of reaction with respect to hydrogen, we need to relate the experiments 1 and 3 in order to get rid of the pressure of ICl:

\frac{r_1}{r_3} =\frac{k*p_{H_2,1}^m*p_{ICl,1}^n}{k*p_{H_2,3}^m*p_{ICl,3}^n}

Thus, we plug in the given rates, and pressures to get:

\frac{1.34}{0.266} =\frac{k*250^m*325^n}{k*50^m*325^n}

So we can cancel wout k and 325^n:

\frac{1.34}{0.266} =\frac{250^m}{50^m}

Next we solve for m, the order of reaction with respect to hydrogen:

5.04 =5^m\\\\log(5.04)=m*log(5)\\\\m=\frac{log(5.04)}{log(5)} \\\\m=1.0

It means it is first-order with respect to hydrogen.

Regards!

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When sodium Cardonate is heated what type of reaction does it form
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Answer:

Thermal Decomposition

Explanation:

7 0
3 years ago
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