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Veseljchak [2.6K]
2 years ago
14

a compound containing only sulfur and nitrogen is by mass; the molar mass is g/mol. what are the empirical and molecular formula

s of the compound?'
Chemistry
1 answer:
kolezko [41]2 years ago
3 0

The chemical compound's empirical formula is NS.

The chemical compound's molecular formula is N4S4.

<h3>What does a chemical empirical formula look like?</h3>
  • The empirical formula of a compound that gives the proportion (ratios) of the elements in the complex but not the precise number or arrangement of atoms is known as an empirical formula.
  • This would be the compound's element to whole number ratio with the lowest value.
<h3>What sort of empirical formula would that be?</h3>
  • The chemical structure of glucose is C6H12O6. Every mole of carbon and oxygen is accompanied by two moles of hydrogen.
  • Glucose has the empirical formula CH2O.
  • Ribose has the chemical formula C5H10O5, which can be simplified to the empirical formula CH2O.

learn more about empirical formula here

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the question you are looking for is

A compound containing only sulfur and nitrogen is 69.6% S by mass; the molar mass is 184 g/mol. What are the empirical and molecular formulas of the compound?

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A 6.35 l sample of carbon monoxide is collected at 55.0◦c and 0.892 atm. What volume will the gas occupy at 1.05 atm and 59.0◦c?
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Answer : The final volume of gas will be, 5.46 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.892 atm

P_2 = final pressure of gas = 1.05 atm

V_1 = initial volume of gas = 6.35 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 55.0^oC=273+55.0=328K

T_2 = final temperature of gas = 59.0^oC=273+59.0=332K

Now put all the given values in the above equation, we get:

\frac{0.892atm\times 6.35L}{328K}=\frac{1.05atm\times V_2}{332K}

V_2=5.46L

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Answer the following questions for this equation: 2 H2 + O2 --&gt; 2 H2O
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Explanation:

                  The balance chemical equation for the synthesis of water is as follow,

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In this equation the moles are specified by the coefficients i.e.

2 moles of H₂ reacting with 1 mole of O₂

2 moles of H₂ producing 2 moles of H₂O

1 mole of O₂ producing 2 moles of H₂O

Hence the molar ratio for O₂ and H₂O can be written as,

                            1 Mole O₂ : 2 Mole H₂O

or,

                           1 Mole O₂ / 2 Mole H₂O

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