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Vlad [161]
4 years ago
6

What happens when iron is placed in a solution containing copper ions?

Chemistry
1 answer:
alexgriva [62]4 years ago
8 0

When an iron is dipped in Copper Sulphate

Solution this reaction between them and

copper sulphate change into blue color to light

green color. This show that iron is more

reactive then copper, it can to replace copper

from CuSO4 , CuSO4 is of blue color and

FeSO4 is light green color.

Hope it helps

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3. Round 87.073 meters to three significant figures. Write your answer in scientific notation. Step 1: 87.073 rounds to _______
Nat2105 [25]

Answer:

see below

Explanation:

3.  87.073 meters to three significant figures.

  = 87.1 meters

2.  Write the number in scientific notation. _____meters​

   = 8.71 x 10 ¹  meters

6 0
3 years ago
Read 2 more answers
Molybdenum (Mo) has a body centered cubic unit cell. The density of Mo is 10.28 g/cm3. Determine (a) the edge length of the unit
ser-zykov [4K]

<u>Answer:</u>

<u>For a:</u> The edge length of the unit cell is 314 pm

<u>For b:</u> The radius of the molybdenum atom is 135.9 pm

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the edge length for given density of metal, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density = 10.28g/cm^3

Z = number of atom in unit cell = 2  (BCC)

M = atomic mass of metal (molybdenum) = 95.94 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell =?

Putting values in above equation, we get:

10.28=\frac{2\times 95.94}{6.022\times 10^{23}\times (a)^3}\\\\a^3=\frac{2\times 95.94}{6.022\times 10^{23}\times 10.28}=3.099\times 10^{-23}\\\\a=\sqrt[3]{3.099\times 10^{-23}}=3.14\times 10^{-8}cm=314pm

Conversion factor used:  1cm=10^{10}pm  

Hence, the edge length of the unit cell is 314 pm

  • <u>For b:</u>

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

R=\frac{\sqrt{3}a}{4}

where,

R = radius of the lattice = ?

a = edge length = 314 pm

Putting values in above equation, we get:

R=\frac{\sqrt{3}\times 314}{4}=135.9pm

Hence, the radius of the molybdenum atom is 135.9 pm

4 0
3 years ago
What is the net charge of a nitrogen atom with 8 electrons
DaniilM [7]

Answer:

– 1

Explanation:

From the question given above, we obtained the following:

Electron = 8

Net charge of nitrogen =.?

Nitrogen has atomic number of 7. This also means that nitrogen has 7 proton because atomic number of an element is the equal to number of protons in the atom of the element.

Thus, we can obtain the net charge of nitrogen with 8 electrons by calculating the difference between the protons and electrons of the nitrogen atom. This can be obtained as follow:

Proton = 7

Electron = 8

Net charge = Proton – Electron

Net charge = 7 – 8

Net charge = – 1

Therefore, the net charge of the nitrogen atom with 8 electrons is – 1

7 0
3 years ago
How do you calculate the atomic mass number ?
anastassius [24]

add up the mass of protons and neutrons

3 0
3 years ago
Read 2 more answers
Instructions:Select the correct answer.
andriy [413]
Activity series of metals: K,Na,Mg,Al,Zn,Fe,Cu,Ag. Metals on the left are more reactive than metals on the right. For example Zn is more reactive than Fe and can displace him. 
Reaction than can occur is: <span>CuSO4(aq) + Fe(s) → FeSO4(aq) + Cu(s).</span>
8 0
3 years ago
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