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hram777 [196]
3 years ago
5

PLS ANSWER FAST WILL GIVE BRAINLEST!!!

Physics
1 answer:
Ad libitum [116K]3 years ago
7 0

Answer:

mass=force/acceleration

m=10/20

m=0.5kg

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A small block with mass 0.0350 kgkg slides in a vertical circle of radius 0.550 mm on the inside of a circular track. During one
Lisa [10]

Answer:

 W_net = μ 5.58,   μ = 0.1     W_net = 0.558 J

Explanation:

The work is defined by the related

          W = F. d ​​= F d cos θ

where bold indicates vectors.

In the case, the work of the friction force on a circular surface is requested.

The expression for the friction force is

              fr = μ N

the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1

               W = - fr d

the path traveled half the length of the circle

               L = 2 π R

               d = L / 2

               d = π R

we substitute

                 W = - μ N d

Total work is initial to

                W_neto = - μ π R (N_b - N_a)

let's calculate

                W_net = - μ π 0.550 (0.670 - 3.90)

                W_net = μ 5.58

for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1

                W_net = 0.1 5.58

                W_net = 0.558 J

7 0
3 years ago
2. After you cross the finish line, you slow
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Answer:

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Explanation:

4 0
3 years ago
The amount of kinetic energy an object has depends on its.
dalvyx [7]
<span>The amount of kinetic energy an object has
depends on its mass and speed.</span>
5 0
3 years ago
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Which statement describes what happens when a balloon is rubbed with a wool cloth?
victus00 [196]
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8 0
3 years ago
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What is the period of a simple pendulum 47 cm long (a) on the Earth, and ( b) when it is in a freely falling elevator?
Liula [17]

Answer:

a)1.37 s

b)∞ ( Infinite)

Explanation:

Given that

L= 47 cm              ( 1 m =100 cm)

L= 0.47 m

a)

On the earth :

Acceleration due to gravity = g

We know that time period of the simple pendulum given as

T=2\pi\sqrt{ \dfrac{L}{g_{{eff}}}

Here

g_{eff}= g

Now by putting the values

T=2\pi \times\sqrt{ \dfrac{0.47}{9.81}}

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b)

Free falling elevator :

When elevator is falling freely then

g_{eff}= 0            ( This is case of weightless motion)

Therefore

T=2\pi\sqrt{ \dfrac{L}{0}

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6 0
4 years ago
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