Since it is dropped, initial velocity u = 0
Using s = ut + (1/2)gt^2, putting u = 0, g = 10 m/s^2
s =(1/2)gt^2, t = 3s
s = 0.5 * 10 * 3 *3
s = 45 m.
The bridge is 45m above the water.
Answer:
H=Hydrogen, PO4=Phosphate
Explanation:
Reactions are on the left side of arrow and products are on the right side of arrow.
They stay in place and vibrate.
Answer:
The total displacement from the starting point is 1.5 m.
Explanation:
You need to sum and substract, depending on the movement (to the right, sum; to the left, substract).
First, it moves 4.3 m right and return 1.1 m. So the new distance from the starting point is 3.2 m.
Second, it moves 6.3 m right, so the new distance is 9.5 m.
Finally it moves 8 m to the left, so 9.5 m - 8 m= 1.5 m.
Summarizing, at the end the squirrel is 1.5 m from its starting point.
