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of oxygen at STP would be required to react completely with 38.8g of propane.
<u>Given that :</u>
molar mass of propane = 44 g/mol
mass of propane = 38.8 g
∴ Moles present in 38.8 g of propane = = 0.88 mole
<u>applying rule of balanced equations </u>
1 mole of propane = 5 moles of oxygen
0.88 mole of propane = 5 * 0.88 = 4.4 moles of oxygen
Note : volume of 1 mole of oxygen at STP =
∴Total volume of oxygen required at STP = 22.4 * 4.4 =
Hence we can conclude that the volume of oxygen at STP required to react completely
Learn more : brainly.com/question/16998374
Answer:
- You may normally expect a <em>slow</em> reaction if a <em>high</em> activation energy is required.
- Or, You may normally expect a <em>fast</em> reaction if a <em>low</em> activation energy is required.
Explanation:
- To answer this question, we should define firstly the term of activation energy.
- The activation energy is the minimum energy must the reacting molecules have to initiate the chemical reaction.
- Also, we can define it as The energy barrier that the molecules must posses an amount of energy equal or more than the value of this barrier.
- So, as the activation energy be of low value, the possibility that the reacting molecules can have this amount of energy to initiate and proceed the reaction increases and the reaction rate also increases.
- Additionally, as the activation energy be of high value, the possibility that the reacting molecules can have this amount of energy to initiate and proceed the reaction decreases and the reaction rate also decreases.
Thus, we can answer this question as:
- You may normally expect a <em>slow</em> reaction if a <em>high</em> activation energy is required.
- You may normally expect a <em>fast</em> reaction if a <em>low</em> activation energy is required.
We use the ideal gas equation in order to calculate the temperature of the system. It is expressed as follows:
PV=nRT
where P is pressure, V is volume, n is the number of moles, R is the universal gas constant and T is the temperature.
15 atm (.1 L) = 0.5 mol (0.08206 L-atm / mol-K) T
T = 36.56 K
Hope this answers the question. Have a nice day.
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