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almond37 [142]
3 years ago
6

Which of the following equations is balanced?

Chemistry
2 answers:
Sauron [17]3 years ago
7 0

Answer:

The first one.

Explanation:

There are 4 hydrogen and 2 oxygen on the reactants side. And there are 4 hydrogen and 2 oxygen on the products side

vaieri [72.5K]3 years ago
6 0

Answer:

The second one

Explanation:

4 Sodium and 2oxygen on the reactant side and 4Sodium and 2oxygen at the product side

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jonny [76]

Answer:

•Li2S is at a low melting point

•NCL3 is a covalent bond

Explanation:

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5 0
3 years ago
Be sure to answer all parts. Nitric oxide (NO) reacts with oxygen gas to form nitrogen dioxide (NO2), a dark brown gas: 2NO(g) +
notka56 [123]

<u>Answer:</u> NO is the limiting reagent in the given reaction and 0.857 moles of NO_2 will be produced.

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is present in less amount and it limits the formation of products.

Excess reagent is defined as the reagent which is present in large amount.

For the given chemical reaction:

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

We are given:

Moles of NO = 0.857 mol

Moles of oxygen = 0.498 mol

By stoichiometry of the reaction:

If 2 moles of NO reacts with 1 mole of oxygen gas.

So, 0.857 moles of NO will react with = \frac{1}{2}\times 0.857=0.4285mol of O_2

As, the given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, NO is considered as the limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

If 2 moles of NO produces 2 moles of nitrogen dioxide gas.

So, 0.857 moles of NO will produce = \frac{2}{2}\times 0.857=0.857mol of NO_2

Hence, NO is the limiting reagent in the given reaction and 0.857 moles of NO_2 will be produced.

6 0
3 years ago
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Greeley [361]
B, the height above or below sea level
3 0
3 years ago
If 25.0 g NO are produced, how many grams of nitrogen gas are used?
ivanzaharov [21]

Based on the assumption that the reaction involves N and O to produce NO, if 25.0 g of NO are produced, the amount of N gas used would be 11.66 grams

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

       N + O ---------> NO

Mole ratio of N to NO is 1:1

Mole of 25.0 g of NO = 25/30.01 = 0.833 moles

Equivalent mole of N = 0.833 moles

Mass of 0.833 moles N = 0.833 x 14 = 11.66 grams

More on stoichiometric calculations can be found here: brainly.com/question/8062886

7 0
2 years ago
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