According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3.
</span>hence proved
I hope this helps la la la
The first one is correct and the others I can't really see the picture is blurry
Answer:
D
Step-by-step explanation:
Since there are two types of values here: tokens and dollars, we will need to use the same value across numerators and denominators in the ratio.
Choice D has 11 tokens over $2 equals to t tokens over $16. In both fractions the numerator is tokens and denominator is dollars.
