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motikmotik
2 years ago
10

3.25 x 10+8 nm2 divide by 6.5 x 10+6 nm =

Chemistry
1 answer:
Vesnalui [34]2 years ago
8 0

Answer:  50 nm

Explanation:  Two steps:

1.  Divide 3.25/6.5 = 0.5

2.  Divide 10^8/10^6 = 10^2

nm^2/nm = nm

Combine:  0.5x10^2 nm

or 50 nm

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Carbon-12 contains 6 protons and 6 neutrons. The radius of the nucleus is approximately 2.7 fm (femtometers) and the radius of t
Slav-nsk [51]

Explanation:

Let us assume that volumes is equal to spheres  volume of nucleus.

fm = femto meter = 10^{-15}

pm = pico meter = 10^{-12}

Hence, calculate the volume as follows.

          V = \frac{4}{3} \times \pi \times r^{3}

              = \frac{4}{3} \times 3.14 \times (2.7)^{3}

              = 82.4481 fm^{3} (cubic femtometers)

or,          = 82 fm^{3}

Now, we will calculate the volume of the atom as follows.

          V = \frac{4}{3} \times \pi \times r^{3}

             = \frac{4}{3} \times 3.14 \times (70)^{3}

             = 1436758.4 pm^{3} (cubic picometers)

thus, we can conclude that volume of the nucleus is 82 fm^{3}  and volume of the atom is 1436758.4 pm^{3}.

7 0
3 years ago
Copper sulfate is a blue solid that is used to control algae growth. Solutions of copper sulfate that come in contact with the s
True [87]

Answer:

185.49 grams of Zinc would react with 454g (1lb) of copper sulfate

Explanation:

Yo know the following balanced reaction:

CuSO₄(aq)+ Zn(s) →Cu(s) + ZnSO₄(aq)

You can see that by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagents and products are part of the reaction:

  • CuSO₄: 1 mole
  • Zn: 1 mole
  • Cu: 1 mole
  • ZnSO₄: 1 mole

Being:

  • Cu: 63.54 g/mole
  • S: 32 g/mole
  • O: 16 g/mole
  • Zn: 65.37 g/mole

the molar mass of the compounds participating in the reaction is:

  • CuSO₄:63.54 g/mole + 32 g/mole + 4*16 g/mole= 159.54 g/mole ≅ 160 g/mole
  • Zn: 65.37 g/mole
  • Cu: 63.54 g/mole
  • ZnSO₄: 65.37 g/mole + 32 g/mole + 4*16 g/mole= 161.37 g/mole

Then, by stoichiometry of the reaction, the following amounts of mass of reagent and product participate in the reaction:

  • CuSO₄: 1 moles* 160 g/mole= 160 g
  • Zn: 1 mole* 65.37 g/mole= 65.37 g
  • Cu: 1 mole* 63.54 g/mole= 63.54 g
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Now you can apply the following rule of three: if 160 grams of CuSO₄ react with 65.37 grams of Zn by this reaction stoichiometry, 454 grams of CuSO₄ with how much mass of Zn will it react?

mass of Zn=\frac{454 grams of CuSO_{4} *65.37 grams of Zn}{160 grams of CuSO_{4}}

mass of Zn= 185.49 grams

<u><em>185.49 grams of Zinc would react with 454g (1lb) of copper sulfate</em></u>

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