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Ahat [919]
3 years ago
9

Calculate the molar solubility of PbCO3 when the Ksp of PbCO3 is 1.5*10^-15 at 25°C.

Chemistry
1 answer:
sertanlavr [38]3 years ago
7 0
First, write the dissociation equation for PbCO3 which is PbCO3 = Pb^(2+) + CO3^(2-). Then, write the Ksp equation which is Ksp = [Pb^(2+)][CO3^(2-)]. The equation suggests that there is 1:1 molar ratio between the Pb^(2+), CO3^(2-) and the dissolved PbCO3. Thus in equation form, we can represent them as x. The Ksp equation is then: 1.5*10^-15 = x^2. The molar solubility of PbCO3, x, is then equal to 3.87*10^-8 moles per liter.
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