Answer:
19 °C
Explanation:
Step 1: Given and required data
- Mass of granite (m): 20 g
- Heat absorbed (Q): 300. 2 J
- Specific heat capacity of granite (c): 0.790 J/g.°C
Step 2: Calculate the temperature change (ΔT)
We will use the following expression.
Q = c × m × ΔT
ΔT = Q/c × m
ΔT = 300.2 J/(0.790 J/g.°C) × 20 g = 19 °C
Answer:
D. The equipment needed to accommodate the high temperature and pressure will be expensive to produce.
Explanation:
Hello!
In this case, for the considered reaction, it is clear it is an exothermic reaction because it produces energy; and therefore, the higher the temperature the more reactants are yielded as the reverse reaction is favored. Moreover, since the effect of pressure is verified as favoring the side with fewer moles; in this case the products side (2 moles of ammonia).
In such a way, the high pressure favors the formation of ammonia whereas the high temperature the formation of hydrogen and nitrogen and therefore, option A is ruled out. Since the high pressure shifts the reaction rightwards and the high temperature leftwards, we would not be able to know whether the reaction has ended or not because it will be a "go and come back" process, that is why B is also discarded. Now, since hydrogen and nitrogen would be the "wastes", we discard C because they are not toxic. That is why the most accurate answer would be D. because it is actually true that such equipment is quite expensive.
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Answer:
you will run 720 meters
Explanation:
because 4 times 60 is 240 and 240 times 3 is 720
A calorimeter experiment is a set-up that provides insulation so that no heat escapes to the surroundings and all energy can be accounted for. It can be done at either constant volume or constant pressure. So, the answer to this is knowing the mass of water, the specific heat which is an empirical data, and the change in temperature which can be measured using a thermometer. This experiment could measure the mass of an unknown substance added or the specific heat of the substance or the calorimeter. <em>The answer is D.</em>
Answer:
Amount left after 140 days is 38.125 g.
Explanation:
Given data:
Half life of Co-59 = 35 days
Total mass of sample = 610.0 g
Sample remain after 140 days = ?
Solution:
Number of half lives passes during 140 days:
Number of half lives = T elapsed / Half lives
Number of half lives = 140 days / 35 days
Number of half lives = 4
Amount left:
At time zero = 610 g
At first half life = 610 g/2 = 305 g
At second half life = 305 g/2 = 152.5 g
At 3rd half life = 152.5 g/2 = 76.25 g
At 4th half life = 76.25 g /2 =38.125 g
Amount left after 140 days is 38.125 g.
