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3 years ago

The earthquake killed about 60 people and was the strongest earthquake to hit

Physics

2 answers:

Soloha48 [4]3 years ago

4 0

I need more information

STatiana [176]3 years ago

3 0

This seems like an incomplete question..

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Object A of mass 0.70 kg travels horizontally on a frictionless surface at 20 m/s. It collides with object B, which is initially

AnnZ [28]

Answer:

25.71 kgm/s

Explanation:

Let K₁ and K₂ be the initial and final kinetic energies of object A and v₁ and v₂ its initial and final speeds.

Given that K₂ = 0.7K₁

1/2mv₂² = 0.7(1/2mv₁²)

v₂ = √0.7v₁ = √0.7 × 20 m/s = ±16.73 m/s

Since A rebounds, its velocity = -16.73 m/s and its momentum change, p₂ = mΔv = m(v₂ - v₁) = 0.7 kg (-16.73 - 20) m/s = 0.7( -36.73) = -25.71 kgm/s.

Th magnitude of object A's momentum change is thus 25.71 kgm/s

6 0

3 years ago

You roll a toy car, and it moves 10 meters in five seconds. What is the car's velocity?

maks197457 [2]

Displacement = 10 m
Time = 5 s
We know,
$velocity \: \: = \frac{displacement}{time} \\$
Therefore, the car's velocity
$= \frac{10}{5} m/s \\ = 2m/s$

<h3>Answer:</h3>

The car's velocity is 2 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

8 0

2 years ago

A wave with a high frequency generally has a _____.

il63 [147K]

High frequency = D, short wavelength

4 0

3 years ago

Why is the physics of hssc2 so difficult?

Ivan

Could be easy for some people and hard for some people.

8 0

3 years ago

Read 2 more answers

An 89.0 kg fullback moving east with a speed of 5.6 m/s is tackled by an 85.0 kg opponent running west at 2.84 m/s, and the coll

Korolek [52]

Answer:

a. $v_f=1.477m/s$

b. Δ $K=1558.3J$

c. $E_k=1034.7 J$

Explanation:

a).

Momentum conserved

$p_{ix}=p_{fx}$

$m_1*v_1+m_2*v_2=(m_1+m_2)*v_f$

$v_f=\frac{m_1*v_1+m_2*v_2}{m_1+m_2}$

$v_f=\frac{89.0kg*5.6m/s+85.0kg*-2.84m/s}{(89.0+85.0)kg}$

$v_f=1.477m/s$

b).

Δ $K=K_i-K_f$

$\frac{1}{2}*m_1*v_1^2+\frac{1}{2}*m_2*v_2^2=\frac{1}{2}*(m_1+m_2)*v_f^2$

$\frac{1}{2}*89.0kg*(5.6m/s)^2+\frac{1}{2}*85.0kg*(2.84m/s)^2=\frac{1}{2}*(89.0+85.0)kg*(1.447m/s)^2$

Δ $K=1558.3J$

c).

$E_k=\frac{1}{2}*89kg*(5.8m/s)^2-\frac{1}{2}*(85+89)kg*(1.44m/s)^2$

$E_k=1034.7 J$

d).

All of which has been lost as mechanical energy, and is now thermal energy warmer football players, noise a loud crunch for example.

8 0

3 years ago