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ruslelena [56]
4 years ago
5

A science-fiction tale describes an artificial "planet" in the form of a band completely encircling a sun. The inhabitants live

on the inside surface (where it is always noon). Imagine that this sun is exactly like our own, that the distance to the band is the same as the Earth-Sun distance (to make the climate temperate), and that the ring rotates quickly enough to produce an apparent gravity of g as on Earth
Physics
1 answer:
arlik [135]4 years ago
6 0

Answer:

8.97 days

Explanation:

Assuming we are asked what will be the period of revolution, this planet's year, in Earth days?

The period of revolution T is given as

T=2\pi\sqrt{\frac{r}{g} }

here, r= distance between planet and its sun which is same as distance between Earth-Sun = 149.7\times10^9 m

g= acceleration due to gravity = 9.81 m/s^2

therefore,

T=2\pi\sqrt{\frac{149.7\times10^9}{9.81} }

=775580 seconds

= 8.97 days

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According to ohms law if you don't change the value of the resistor and you double the voltage in a circuit the amount of curren
padilas [110]

Answer: D (doubled)

According to ohm's law

                      I = V/R ,

                      V = IR ;   R = constant and V is doubled

  From the equation

                      V is directly proportional to the current, and it is given that R is constant ;

                    2V = 2I. R    since R = constant

                      Hence I is doubled.

                     

                   

5 0
4 years ago
NEED HELP TODAY
Free_Kalibri [48]

Answer:

I am pretty sure it is B My friend hope you are well

Explanation:

6 0
3 years ago
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A car with good tires on a dry road can decelerate (slow down) at a steady rate of about 5.0 m/s2 when braking. if a car is init
Sladkaya [172]

The time required by the car to stop is 4.916 sec.

Since the car is moving with the constant deceleration we can apply the first equation of motion to calculate the time required by the car to stop.

The first equation of motion is given as

V=u+at

Here, V=final speed of the car=0 mi/h as the car stops

u =initial speed of the car=55 mi/hr=24.58 m/s

a= acceleartion =-5 m/s^2 (here negative sign indicates for deceleration)

Now applying the values in the first equation

V=u+at

0=24.58-5*t

t=4.916 sec

Therefore the car will stops in 4.916 sec.

8 0
3 years ago
The sun has sufficient hydrogen to continue fusing into helium for how much longer?
vichka [17]

Answer:

4500 million years

Explanation:

The Sun shines thanks to the thermonuclear conversion of hydrogen to helium inside. It is currently 4,500 million years old and has reservations for a similar period of time. When this fuel is exhausted in the central region, the heart of the Sun, constituted of helium and in an inert state, will contract and put more external fuel reserves within reach of the star, with which this mass of helium will grow over time . When that happens, the Sun will evolve into a giant star that will reach the orbit of Mars and, therefore, destroy the planet Earth.

As the helium heart mass increases so do the central density and temperature. When it reaches 100 million degrees, helium fuses thermonuclearly with itself and becomes a mixture of carbon and oxygen.

When the helium runs out in the center, the previous operation is reproduced approximately. The carbon / oxygen heart contracts and the helium and hydrogen of the surrounding layers are placed within the reach of thermonuclear combustion. The difference is that this double combustion is unstable and the density is so high that electrons can, alone, stabilize the heart of carbon and oxygen. The end result is that the outer layers, which originate a planetary nebula, are expelled, and the old thermonuclear reactor becomes visible, which becomes a white dwarf that slowly cools like the embers of a fire over billions of millions. of years.

8 0
3 years ago
If the current through a 20-Ω resistor is 8.0 A , how much energy is dissipated by the resistor in 1.0 h ? Express your answer w
marshall27 [118]

Answer:

P(3600)=593.247W

Explanation:

First, let's find the voltage through the resistor using ohm's law:

V=IR=20*8=160V

AC power as function of time can be calculated as:

P(t)= V*I*cos(\phi)-V*I*cos(2 \omega t-\phi)  (1)

Where:

\phi=Phase\hspace{3}angle\\\omega= Angular\hspace{3}frequency

Because of the problem doesn't give us additional information, let's assume:

\phi=0\\\omega=2 \pi f=2*\pi *(60)=120\pi

Evaluating the equation (1) in t=3600 (Because 1h equal to 3600s):

P(3600)=160*8*cos(0)-160*8*cos(2*120\pi*3600-0)\\P(3600)=1280-1280*cos(2714336.053)\\P(3600)=1280-1280*0.5365255751\\P(3600)=1280-686.7527361=593.2472639\approx=593.247W

5 0
4 years ago
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