To solve this problem it is necessary to apply the concepts related to Young's Module and its respective mathematical and modular definitions. In other words, Young's Module can be expressed as

Where,
F = Force/Weight
A = Area
= Compression
= Original Length
According to the values given we have to




Replacing this values at our previous equation we have,



Therefore the Weight of the object is 3.82kN
Answer:
Explanation:
In wheel and axle. …with the system is the velocity ratio, or the ratio of the velocity (VF) with which the operator pulls the rope at F to the velocity at which the weight W is raised (VW). This ratio is equal to twice the radius of the large drum divided by the difference…
Answer:
Force exerted, F = 2.64 × 10⁷ Newton
Explanation:
It is given that,
Mass of the artillery shell, m = 1100 kg
It is accelerated at, 
We need to find the magnitude of force exerted on the ship by the artillery shell. It can be determined using Newton's second law of motion :
F = ma

F = 26400000 Newton
or
F = 2.64 × 10⁷ Newton
So, the force exerted on the ship by the artillery shell is 2.64 × 10⁷ Newton.
Newton's First Law: An object in motion stays in motion, an object at rest stays at rest unless an unbalanced force acts upon it. For example, when zipping down the zip line you will stay in motion unless an outside force interferes. ... The more mass the more force needed.
Answer:
the fundamental frequency produced by the open pipe is 120.78 Hz
Explanation:
Given;
length of the open pipe, L = 1.42 m
speed of sound in air, v = 343 m/s
The length of the open pipe for the fundamental frequency is equivalent to half of wavelength;

The fundamental frequency produced by the open pipe is calculated as;

Therefore, the fundamental frequency produced by the open pipe is 120.78 Hz