A piece of fruit is hanging from a tree what energy is being used

You watch distant Sally Homemaker driving nails into a front porch at a regular rate of 1 stroke per second. You hear the sound

denpristay [2]

Answer: 343meters away

Explanation:

The velocity of sound in air is approx 343m/s

SO,

Velocity = distance/time taken.

The time taken is 1second only.

Distance = velocity × time

Distance = 343 × 1 = 343meters.

6 0

2 years ago

To open a soda can lid, a force of 50 N is applied to a car key, which acts as a lever. If the car key applies a force of 400 N

kati45 [8]

Explanation:

Given. Required

wo = 400N. MA=?

wi = 50N

Solution

MA = wo = 400N =8

wi. 50N

4 0

2 years ago

A hollow cylinder is given a velocity of 5.3 m/s and rolls up an incline to a height of 2.87 m. If a hollow sphere of the same m

Valentin [98]

Answer:

E = 1/2 M V^2 + 1/2 I ω^2 = 1/2 M V^2 + 1/2 I V^2 / R^2

E = 1/2 M V^2 (1 + I / (M R^2))

For a cylinder I = M R^2

For a sphere I = 2/3 M R^2

E(cylinder) = 1 + 1 = 2 omitting the 1/2 M V^2

E(sphere) = 1 + 2/3 = 1.67

E(cylinder) / E(sphere) = 2 / 1.67 = 1.2

The cylinder initially has 1.20 the energy of the sphere

The PE attained is proportional to the initial KE

H(sphere) = 2.87 / 1/2 = 2.40 m since it has less initial KE

5 0

1 year ago

After the first few seconds of a race, a runner runs at the same speed until she approaches the finish line, at which point she

Rzqust [24]

DUJFIOflmC VANWSER

EXPLANTATION

5 0

2 years ago

An engineer has the task of producing an aluminum alloy with a density of 3.0 grams per cubic centimeter. She comes up with the

pochemuha

Answer:

The best option is for the following option m = 15 [g] and V = 5 [cm³]

Explanation:

We have that the density of a body is defined as the ratio of mass to volume.

$Ro =m/V$

where:

Ro = density = 3 [g/cm³]

Now we must determine the densities with each of the given values.

For m = 7 [g] and V = 2.3 [cm³]

$Ro=7/2.3\\Ro=3.04 [g/cm^{3} ]$

For m = 10 [g] and V = 7 [cm³]

$Ro=10/7\\Ro=1.42[g/cm^{3} ]\\$

For m = 15 [g] and V = 5 [cm³]

$Ro=15/5\\Ro=3[g/cm^{3} ]\\$

For m = 21 [g] and V = 8 [cm³]

$Ro=21/8\\Ro=2.625[g/cm^{3} ]\\$

5 0

2 years ago