A piece of fruit is hanging from a tree what energy is being used

A spacecraft is separated into two parts by detonating the explosive bolts that hold them together. The masses of the parts are

nordsb [41]

Answer:

0.279 m/s

Explanation:

mass (m1) = 1150 kg

mass (m2) = 1900 kg

impulse (J) = 200 N.s

With what relative speed do the two parts separate because of the detonation?

since both parts separate, their relative speed = speed of m1 + speed of m2

speed of m1 = $\frac{J}{m}$ = $\frac{200}{1150}$ = 0.174 m/s

speed of m2 = $\frac{J}{m}$ = $\frac{200}{1900}$ = 0.105 m/s
relative speed = 0.174 + 0.105 = 0.279 m/s

6 0

3 years ago

numerade A 62 kg bungee jumper jumps from a bridge. She is tied to a bungee cord whose unstretched length is 12 m. She falls a t

GalinKa [24]

Answer:

k = 104.5 N/m

Explanation:

When she reaches the lowest point the velocity of the jumper is 0. This means all her kinetic energy has been absorbed by the cord.

The energy absorbed by a spring (a cord can be treated as a spring when it's being stretched) is:

$Ee = \frac{1}{2}*k*\Delta x^{2}$

Where:

Ee = elastic potential energy

k = elastic constant

Δx = lenght the spring was stretched

When a body falls, it's potential gravitational energy is converted to kinetic energy. So the kinetic energy of a body can be calculated as the gravitational potential energy it lost.

The gravitational potential energy is:

$Ep = m * g * \Delta h$

Where:

Ep: potential gravitational energy

m: mass

g: acceleration of gravity

Δh: change of height (final - initial)

When she has fallen 31 m she has lost

62 kg * 9.81 m/s^2 * 31 m = 18854 J

Since her velocity at the bottom is 0, her kinetic energy is 0 J.

All her kinetic energy has been absorbed by the cord and transformed into elastic potential energy. So we can equate these two energies.

Ep = Ee

Then:

$Ep = \frac{1}{2}*k*\Delta x^{2}$

Δx = 31 m - 12 m = 19 m

From here the only unknown is k:

$k = 2 * Ep / (\Delta x ^{2})$

$k = 2 * 18854 J / ((19 m) ^{2}) = 104.5 N/m$

3 0

3 years ago

A muon is a short-lived particle. It is found experimentally that muonsmoving at speed 0.9ccan travel about 1500 meters between

Monica [59]

Answer:

a) $t=5.5\mu s$

b) $\Delta t'=12.5\mu s$

Explanation:

a) Let's use the constant velocity equation:

$v=\frac{\Delta x}{\Delta t}$

v is the speed of the muon. 0.9*c
c is the speed of light 3*10⁸ m/s

$t=\frac{\Delta x}{v}=\frac{1500}{0.9*(3*10^{8})}$

$t=5.5\mu s$

b) Here we need to use Lorentz factor because the speed of the muon is relativistic. Hence the time in the rest frame is the product of the Lorentz factor times the time in the inertial frame.

$\Delta t'=\gamma\Delta t$