The percent increase in enrollment is 6 %
The operation used in first step is finding the difference between final value and initial value
<h3><u>Solution:</u></h3>
Given that This year, 1,272 students enrolled in night courses a a local college
Last year only 1,200 students enrolled.
To find: percent increase in the enrollment
The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.
<em><u>The percent increase is given as:</u></em>
Here initial value (last year) = 1200 and final value(this year) = 1272
Substituting the values in above formula,
Thus percent increase is 6 %
Answer:
x^6/27y^12
Step-by-step explanation:
(3. 1?x^2 y^4)^3
(3y^4/x^2)^3
witch you get x^6/27y^12
hope i helped
12 3/4 as a decimal is 12.75
The area of a rectangle is length times width.
So if you divide the area (12.75) by the length(3.4)
you will get a width (and answer) of 3.75 :)
A.) A = 20000 + 1000n
B = 20000(1.04)^n
b.) For A, sn = n/2(2a + (n - 1)d)
s20 = 20/2(2(20000) + 1000(20 - 1)) = 10(40000 + 19(1000)) = 10(40000 + 19000) = 10(59000) = $590,000
For B, sn = a(r^n - 1)/(r - 1)
s20 = 20000((1.04)^20 - 1)/(1.04 - 1) = 20000(2.191 - 1)/0.04 = 20000(1.191)/0.04 = 23822.46 / 0.04 = $595,561.57
c.) Using a graphing calculator, it takes 18 years for the
<span>total amount earned a company B is greater that the total amount of earned at company A.</span>
