Answer:
305.88 g
Explanation:
4 Al + 3 O₂ → 2 Al₂O₃
First, we <u>convert 6 moles of aluminum (Al) into moles of aluminum oxide (Al₂O₃)</u>, using the <em>stoichiometric coefficients</em>:
6 mol Al * = 3 mol Al₂O₃
Finally we <u>convert 3 moles of aluminum oxide into grams</u>, using its<em> molar mass</em>:
3 mol Al₂O₃ * 101.96 g/mol = 305.88 g
Answer:
- 3706.5 J.
Explanation:
The heat lost by the copper can be calculated using the formula:
Q = m.C.ΔT, where,
Q is the amount of heat lost by the mercury,
m is the mass of the copper <em>(m = 75.0 g)</em>,
C is the specific heat of Hg <em>(C = 0.140 J/g.°C)</em>,
ΔT is the temperature difference (the final temperature - the initial temperature<em> (ΔT = (297 K - 273) °C - (650 K - 273) °C = - 353 °C)</em>.
∴ The amount of heat lost by the mercury Q = m.C.ΔT = (75.0 g) (0.140 J/g.°C) (- 353 °C) = - 3706.5 J.
It would be c because it has to get hot so it is absorbing the heat not releasing it
Answer:
589.8 kJ/mol
Explanation:
Let's consider the process in which <em>the most loosely bound electron from each atom in a mole atom of gaseous calcium is removed.</em>
Ca(g) + Energy ⇒ Ca¹⁺(g) + 1 e⁻
The energy involved in this process is known as First Ionization Energy. The First Ionization Energy for calcium is 589.8 kJ/mol.
Answer: C- 1.65 moles
Explanation:
HCl = 1 + 35.45 = 36.45 g/mol