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sergiy2304 [10]

2 years ago

5

Inside an atom, which of these occupies the maximum volume? a) the electrons b) the protons c) the neutrons d) empty space (vacu

um)

1 answer:

icang [17]2 years ago

3 0

Answer: Electrons

Explanation:The electron itself is small but it takes space as much as an atom by circling around the nucleus.

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So anyone wanna be a Good Samaritan and help ya girl out

goldenfox [79]

The answer is JESUS BECAUSE HE IS ALWAYS THE ANSWER

8 0

3 years ago

Power gathered from the sun and wind

Mademuasel [1]

Answer: B. Can provide humans with energy forever

Explanation: The warm air rises and cooler air rushes in to take its place. The moving air is wind. As long as the sun shines, there will be winds on the Earth. We will never run out of wind energy.

7 0

2 years ago

Read 2 more answers

A scientist finds that one volume of an unknown gas X combines with two volumes of another gas Y to form two volumes of a new ga

MariettaO [177]

Answer:

Gas X

Explanation:

The given reaction can be written in the form of chemical equation as shown below as:

$X+2Y\rightarrow 2XY_2$

According to law of conservation of mass, the moles of each substance in the reaction must be equal on both reactant and product side.

Also, the question asks for the gas which is diatomic. $XY_2$ cannot be diatomic as the formula contains 3 atoms.

Between gas X and gas Y , <u>X has to be diatomic for the reaction to balance </u>as:

$X_2+2Y\rightarrow 2XY_2$

3 0

3 years ago

How many grams of Na2SO4 can be produced from 423.67 g of NaCl?

san4es73 [151]

Mass of Na2SO4= 514.18 grams

<h3>Further explanation</h3>

Given

423.67 g of NaCl

Required

mass of Na2SO4

Solution

Reaction

2NaCl + H2SO4 → Na2SO4 + 2HCl

mol NaCl :

= 423.67 g : 58.5 g/mol

= 7.24

From the equation, mol Na2SO4 :

= 1/2 x mol NaCl

= 1/2 x 7.24

= 3.62

Mass Na2SO4 :

= 3.62 mol x 142,04 g/mol

= 514.18 grams

4 0

2 years ago

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree

lions [1.4K]

Answer:

The new temperature of the water bath 32.0°C.

Explanation:

Mass of water in water bath ,m= 8.10 kg = 8100 g ( 1kg = 1000g)

Initial temperature of the water = $T_1=33.9^oC=33.9+273K=306.9 K$

Final temperature of the water = $T_2$

Specific heat capacity of water under these conditions = c = 4.18 J/gK

Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J

( 1kJ=1000 J)

$Q=m\times c\times \Delta T=m\times c\times (T_2-T_1)$

$-69.0\times 1000 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)$

$-69,000.0 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)$

$T_2=304.86 K=304.86 -273^oC=31.86^oC\approx 32.0^oC$

The new temperature of the water bath 32.0°C.

5 0

3 years ago